Find the mean 9,1,8,3,2,1 graphically.
1 answer:
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Answer:
Solution is 1 (one).
Step-by-step explanation:
- The equation
can be solved by solving first the expression in the numerator. This is done by solving
.
- Then, you just have
. The negative is canceled when it appears twice, so we just have to solve
(any number divided by itself equals to one).
Answer:
We have to prove that,
|P(A)| = , if |A| = n for n = 0, 1, 2, 3.
For n = 0,
A = {}
P(A) = { {} } = = 1
For n = 1,
A = { a } ( suppose )
P(A) = { {}, a } = = 2,
For n = 2,
A = { a, b }
P(A) = { {}, {a}, {b}, {a, b} = = 4,
For n = 3,
A = { a, b, c },
P(A) = { {}, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c} } = = 8
Thus, it is verified for n = 0, 1, 2, 3.
Now, suppose it is valid for a set B having k elements,
That is, |P(B)| =
Also, there is a set A,
Such that, A = B ∪ {x}
Since, after including the element x in set B,
The element x will be come with every element of set B in the power set of B,
i.e. P(A) = =
=
=
Hence, by the induction it has been proved,
|P(A)| = , if |A| = n, Where, n∈ N ( set of natural numbers )