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Anvisha [2.4K]
3 years ago
6

2, 8, 32, 128, 512, ... Find the common ratio

Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

8

Step-by-step explanation:

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What is m∠ MHJ?<br> 35<br> 50<br> 72.5<br> 92.5
NNADVOKAT [17]

Answer:

50

Step-by-step explanation:

MHJ and LHK are vertical angles, which means they are equal

2x-20 = x+15

Subtract x from each side

2x-20-x = x+15-x

x-20 = 15

Add 20 to each side

x-20+20 = 15+20

x = 35

We want to find MHJ

MHJ =2x-20

        =2(35) -20

       = 70 -20

      = 50

3 0
4 years ago
Read 2 more answers
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}&#10;

                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}&#10;

                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}&#10;

                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
A semi circle shaped rug has a diameter of 2 feet what is the area of the rug
Hitman42 [59]
For the full circle, Area = pi(r)^2
pi x 1^2 = pi 
Semi circle = pi/2 = 1.57 square feet
3 0
3 years ago
Can someone please answer this math problem and show your working
Jobisdone [24]
X=7 so that means replace all the x values with 7
7^3+5(3)= the answer solve it
7 square 3 + 5 times 3 equal

6 0
3 years ago
Each bag of apples weighs 4 1/2 lb how much do 6 bags weigh?
Serjik [45]

Answer:

The bags would weigh 27lbs. multiply 4 1/2 and6 and you get 27lbs.

4 0
4 years ago
Read 2 more answers
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