Given that t<span>he
average commute time to work (one way) is 25 minutes according to the
2005 american community survey. if we assume that commute times are
normally distributed and that the standard deviation is 6.1 minutes,
what is the probability that a randomly selected commuter spends less
than 18 minutes commuting one way
The probability that a randomly selected number from a normally distributed dataset with a mean of μ and a standard deviation of σ is less than a value, x, is given by:
</span><span>

Given that the average </span><span>commute time to work (one way) is 25 minutes and that the standard deviation is 6.1 minutes,
the
probability that a randomly selected commuter spends less than 18
minutes commuting one way is given by:

</span>
It would be true. (4+2)(3^2)-6+2*3=54 is true
Hope this helps :)
can you please make this the brainiest answer it would really help
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Answer:
Regular hourly rate for Brandon is $30
Step-by-step explanation:
Let the payment for regular hours be $x
given that
Brandon is paid 150% of his regular hourly rate for overtime hours
payment for overtime hours = 150% of payment for regular hours
payment for overtime hours = 150/100 * x = 3x/2
Given that He is paid \$45.00 an hour for overtime hours
thus,
3x/2 = 45
=> x = 45*2/3 = 30
Thus, regular hourly rate for Brandon is $30
Answer:
12
Step-by-step explanation:
24/6=4 4x3=12