Answer:
Q = 1147.5 cal
Explanation:
Given data:
Energy absorbed = ?
Mass of water = 75 g
Initial temperature = 22.5°C
Final temperature = 37.8°C
Specific heat of water = 1 cal/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2- T1
ΔT = 37.8°C - 22.5°C
ΔT = 15.3 °C
Q = m.c. ΔT
Q = 75 g . 1 cal/g.°C . 15.3 °C
Q = 1147.5 cal
Answer: Is this like a question cause that is what u think
Explanation:
Mostly soil rock with a very thin layer of soil on top.
From equation;
P1V1=P2V2
V2=P1V1÷P2
since P2=380mmHg
now;1atm=760mmHg
how about 380mmHg is equal to how many atm?
380×1÷760=0.5atm
P2 now is equal to 0.5atm
back from equation;
P1V1=P2V2
V2=P1V1÷P2
V2=4.0atm×2.0L÷0.5atm
V2=16L
therefore V2=16L.
Answer:
The correct answer is - 1. oxaloacetate.
Explanation:
During the electron transport chain, the oxaloacetate is converted to aspartate by the reduction of NADH and accepting electrons in the mitochondria. Aspartate is then moved through the inner membrane to the cytosol.
This is the reaction also known as the synthesis of the aspartate. Aspartate either again converted to OAA (oxaloacetate) or move to the biosynthesis of proteins and biosynthesis of purine and pyrimidines.