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3 years ago

15

Relative to Delhi, Mumbai and Kolkata are located opposite to each other. Name city of India which is located opposite to Bangal

ore as related to Delhi.

1 answer:

Mkey [24]3 years ago

7 0

Answer:

Mumbai and Kolkata are located opposite to each other. Haryana is located to opposite to Bangalore as related to Delhi.

Answer From Gauth Math

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Show that there is no solution for the radical equation 4w+4=-4.

Ad libitum [116K]

Answer:

there is a solution

w= -2

Step-by-step explanation:

4w+4=-4

-4 -4

4w=-8

/4 /4

w=-2

3 0

3 years ago

If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)

erica [24]

<u>Given</u>:

Given that ABCD is a rectangle.

The diagonals of the rectangle are AC and DB.

The length of AE is (6x -55)

The length of EC is (3x - 16)

We need to determine the length of the diagonal DB.

<u>Value of x:</u>

The value of x can be determined by equating AE and EC

Thus, we have;

$AE=EC$

Substituting the values, we get;

$6x-55=3x-16$

$3x-55=-16$

$3x=39$

$x=13$

Thus, the value of x is 13.

<u>Length of AC:</u>

Length of AE = $6(13)-55=78-55=23$

Length of EC = $3(13)-16=39-16=23$

Thus, the length of AC can be determined by adding the lengths of AE and EC.

Thus, we have;

$AC=AE+EC$

$AC=23+23$

$AC=46$

Thus, the length of AC is 46.

<u>Length of DB:</u>

Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.

Hence, we have;

$AC=DB$

$46=DB$

Thus, the length of DB is 46.

6 0

2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

you are working to save money for a trip you need to save at least 1000 dollars if you already have 350 saved and you make $8 an

4vir4ik [10]

$1000 dollars is how much you need to pay for the trip.
You already have $350.
$1000 - $350 = $650. So, you need to make $650 more.
$650 <span>÷ 8 = 81.25

So you final answer is: 81.25 hours.

Hope this helped you! :D

</span>

8 0

3 years ago

In this assignment, you will explore how the volume is changed when you adjust the height or radius of a cylinder. You will drag

lesantik [10]

The volume of a cylinder changes when you adjust the height or radius as the volume either increases or reduces.

<h3>How to illustrate the volume?</h3>

Let's assume that the height and radius are 14cm and 7cm. The volume will be:

= πr²h

= 3.14 × 7² × 14

= 2154.04cm³

When the radius and height are reduced to 5cm and 9cm, the volume will be:

= πr²h

= 3.14 × 5² × 9

= 706.5cm³

This illustrates that the volume reduces when the height and radius reduces.

Learn more about volume on:

brainly.com/question/1972490

#SPJ1

8 0

2 years ago