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Alinara [238K]
3 years ago
12

Please help if you can

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

x= 10

Step-by-step explanation:

(whole secant) x (external part) =  (whole secant) x (external part)

(8+x) * 8 = (9+-3+x) * 9

8(8+x) = 9(6+x)

Distribute

64+8x=9x+54

Subtract 8x from each side

64 = x+54

Subtract 54 from each side

10 =x

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Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ
Ivan

Answer:

(-\infty,3)

Step-by-step explanation:

We are given that

(x-3)y''+4y=x

y''+\frac{4}{x-3}y=\frac{x}{x-3}

y(0)=0

y'(0)=1

By comparing with

y''+p(x)y'+q(x)y=g(x)

We get

p(x)=\frac{4}{x-3}

g(x)=\frac{x}{x-3}

q(x)=0

p(x),q(x) and g(x) are continuous for all real values of x except 3.

Interval on which p(x),q(x) and g(x) are continuous

(-\infty,3)and (3,\infty)

By unique existence theorem

Largest interval which contains 0=(-\infty,3)

Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=(-\infty,3)

7 0
3 years ago
What 228,643 to the nearest hundred
Annette [7]
228,643 to the nearest hundered is 228,600.
3 0
4 years ago
I need help please, I am so confused.​
vazorg [7]

Answer:

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point:  the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward.  As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation:  y=x(x-2)

\implies x(x-2)=0

\implies x=0

\implies (x-2)=0 \implies x=2

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: y=(x-4)(x+5)

\implies (x-4)(x+5)=0

\implies (x-4)=0 \implies  x=4

\implies (x+5)=0 \implies x=-5

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: y=-5x(3-x)

\implies -5x(3-x)=0

\implies -5x=0 \implies x=0

\implies (3-x)=0 \implies x=3

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}

4 0
2 years ago
How do I solve for x and what equation do I use to solve
Yuri [45]
You didnt show the rest of the picture i can't help if i can't see.
8 0
3 years ago
Eighteen students decide they don't want to be
Ratling [72]

Answer: 45

Step-by-step explanation:

18 = 40% N

18 = 0.4 N

Divide both sides by 0.4

N = 45

6 0
3 years ago
Read 2 more answers
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