T= 3.34
Vi= 0
A= 9.81
D= ?
d=Vit+1/2at^2
d= 1/2(9.81)(3.34)2
d= 54.7 or 55 meters tall
Answer:
x = 0.6034 m
Explanation:
Given
L = 5 m
Wplank = 225 N
Wman = 522 N
d = 1.1 m
x = ?
We have to take sum of torques about the right support point. If the board is just about to tip, the normal force from the left support will be going to zero. So the only torques come from the weight of the plank and the weight of the man.
∑τ = 0 ⇒ τ₁ + τ₂ = 0
Torque come from the weight of the plank = τ₁
Torque come from the weight of the man = τ₂
⇒ τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)
⇒ τ₂ = Wman*x = 522 N*x (clockwise)
then
τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0
⇒ x = 0.6034 m
Answer:
I'm not completely sure, but I believe the first and third of the three are mechanical.
Explanation:
Chemical potential isn't moving or about to go into motion. It can't be mechanical.
Answer:
I am explain you in image
Answer:
magnitude of net magnetic field at given point is
Explanation:
As we know that magnetic field due to a long current carrying wire is given as
here we we will find the magnetic field due to wire which is along x axis is given as
r = 2 m
now we have
into the plane
Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as
r = 2 m
now we have
along + x direction
Since the two magnetic field is perpendicular to each other
So here net magnetic field is given as
