Close the switch would be the correct answer
Answer:
a) 4.2m/s
b) 5.0m/s
Explanation:
This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.
The problem is also an illustration of elastic collision where there is no loss in kinetic energy.
Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses 
and 
whose respective velocities before collision are 
and 
;
where 
and 
are their respective velocities after collision.
Given;
Note that =0 because the second mass was at rest before the collision.
Also, since the two masses are equal, we can say that 
so that equation (1) is reduced as follows;
m cancels out of both sides of equation (2), and we obtain the following;
a) When 
, we obtain the following by equation(3)
b) As stops moving 
, therefore,
Nothing at all it can't get
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Answer:
AT
Explanation:
Dimensions of current = A
Dimensions of time = T
Current = Charge / time
Therefore Charge = Current × time
[Charge] = [Current] × [time]
= AT
Pressure is defined as the force per unit area. This measurement is more convenient to use for describing a force exerted. The standard unit for pressure is Pascal. For this problem, force is the gravitational pull from the block. Calculations are as follows:
P = F/A where F = mg
F = 7.5 ( 9.81) = 73.6 N
<span>P = 73.6 N / 0.6 m^2 = </span><span>122.5 Pa
Thus, the answer is D.</span>
