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pochemuha
3 years ago
6

Why is it cold in the mountains if heat rises?

Physics
1 answer:
hjlf3 years ago
6 0

Answer:

look at explanation

Explanation:

If heat rises, then why is it so cold at the top of a mountain? Heat does indeed rise. More specifically, a mass of air that is warmer than the air around it expands, becomes less dense, and will therefore float atop the cooler air. ... So when warm air rises, it cools off.

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A surface completely surrounds a 3.3 × 10-6 C charge. Find the electric flux through this surface when the surface is (a) a sphe
KengaRu [80]

Answer:

Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

Explanation:

given,

surface charge (q) = 3.3 × 10⁻⁶ C

to calculate electric flux = ?

a) radius = 0.76 m

area of sphere = 4 π r²

electric flux = \dfrac{q}{\varepsilon}

\varepsilon = 8.85 \times 10^{-12} C^2/Nm^2

electric flux =  \dfrac{3.3 \times 10^{-6}}{8.85 \times 10^{-12} }

flux = 0.373 × 10 ⁶ N m²/C

electric flux in the other two cases will also be same as electric flux is independent of area

so, Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

5 0
4 years ago
High-frequency electromagnetic waves have
Pachacha [2.7K]

Itinuring na isa sa pinakamabangis na heneral sa kanyang panahon, pinalitan niya si Artemio Ricarte bilang Commanding General ng Pilipinas. Army.

7 0
3 years ago
Which is heavier, the earth or the moon
Aloiza [94]

When you say "heavy", you're talking about the gravitational force
between that object and another object, so it depends on what the
"other object" is.

If the "other object" is, let's say, the sun, then the gravitational attraction
between the Earth and sun is about 80 times as much as the gravitational
attraction between the Moon and sun, because the Earth has about 80 times
the mass of the Moon.

But if, somehow, the weight you have in mind is the gravitational attraction
between the Earth and the Moon, then those forces are equal.  The force
of gravity between two objects depends on the product of both masses,
and it's equal in both directions.

If that isn't clear to you, let me give you this additional fact that's guaranteed
to knock you even further off-balance:

Your weight on the Earth is determined by the product of

                           (your mass) times (the Earth's mass).

The Earth's weight on you is determined by the product of

                           (your mass) times (the Earth's mass).

Your weight on Earth is the same as the Earth's weight on you.

Would you like to prove it ?

-- Turn the bathroom scale upside-down, so that the step-pad
    is on the floor.

-- Then step on it, so that you're standing on the bottom, which
    is facing up.

-- If you placed a little mirror on the floor, so that you can read
   the numbers, which are facing down toward the floor, you'll
   read your own weight, even though with the scale upside-down,
   you're weighing the Earth on you.

5 0
3 years ago
A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm
Sergio [31]

Answer:

a) k = 200 N/m

b) E = 4 J

c) Δx = 6.3 cm

Explanation:

a)

  • In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:

       F = - k * \Delta x (1)

  • where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).
  • Solving for k:

       k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)

b)

  • Assuming no friction present, total mechanical energy mus keep constant.
  • When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:

        U = \frac{1}{2}* k* (\Delta x)^{2} (3)

  • Replacing k and Δx by their values, we get:

       U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)

c)

  • When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
  • We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).
  • So, we can write the following expression:

        \frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2}  = \frac{1}{2}*k*\Delta x^{2}   (5)

  • Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:

        \frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2}  = 4J   (6)

⇒      \frac{1}{2}* 200N/m* \Delta x_{1} ^{2}   = 4J  - 3.6 J = 0.4 J (7)

⇒     \Delta x_{1}   = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)

6 0
3 years ago
QUICK HELP PLEASE!
IgorLugansk [536]

Answer:

60/90

Explanation:

I think because the train's highest velocity is 60 n the time is 90

5 0
3 years ago
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