The mass of the quarterback is 61.2 kg.
Explanation:
mass of the football player = m1 = 102 kg
mass of the quarterback = m2 = ?
velocity of the football player = v1 = 8 m/s
According to the law of conservation of momentum:
The total momentum of a system before and after the collision remains constant. Assuming the situation as an isolated system which is not affected by any external factors, we have:
m₁v₁ + m₂v₂ = (m₁+m₂)V
Here, we need to find m₂.
We assume that the quarterback is standing still when he is attacked by the football player so v₂ = 0 m/s
After the collision both of them fall to the ground with a velocity of 5 m/s so V = 5 m/s

Keywords: momentum, velocity, law of conservation of momentum
Learn more about Law of Conservation of Momentum from brainly.com/question/7538238
#learnwithBrainly
Acceleration = change in velocity/time
= 40/5
=8m/s^2
The black squirrel has zero kinetic energy (if it's not moving) and lower gravitational potential energy than the red squirrel or zero gravitational potential energy if the ground is assumed to be zero gravitational potential line.
Answer: Some places like Florida and California are both very hot and dry places, the sun damages your skin more in sunny places then in colder more breezy places.
Explanation:
Answer:
a) Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B
Explanation:
a) Statement A : 2.567km to two significant figures.
2.567km 2. S.F = 2.6km
Statement B : 2.567km to three significant figures.
2.567km 3 S.F = 2.57km
Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) statement A: (2.567 km + 3.146km) to 2 S.F
(2.567km + 3.146km) = 5.713km to 2 S.F = 5.7km
Statement B : (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
2.567km to 2 S.F = 2.6km
3.146km to 2 S.F = 3.1km
2.6km + 3.1km = 5.7km
Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B