Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / 
~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
C++
Explanation:
Significant object-oriented languages include: (list order based on TIOBE index) Java, C++, C#, Python, R, PHP, Visual Basic.NET, JavaScript, Ruby, Perl, Object Pascal, Objective-C, Dart, Swift, Scala, Kotlin, Common Lisp, MATLAB, and Smalltalk.
Answer:
The Anonymous Block will be:
1 DECLARE
2
3 lv_grade_row grade%rowtype;
4 lv_gr_avg grade.gr_t1%type;
5 lv_std_name varchar2(80);
6 cursor cursor_grade is select * from grade;
7
8 BEGIN
9
10 select avg(gr_t1) INTO lv_gr_avg from grade;
11 open cursor_grade;
12 fetch cursor_grade INTO lv_grade_row;
13
14 while cursor_grade%found loop
15
16 if
17 lv_grade_row.gr_t1>lv_gr_avg then lv_std_name :=
lv_grade_row.std_fname|| ' ' ||lv_grade_row.std_lname|| ' ' ||
lv_grade_row.gr_t1;
18 dbms_output.put_line(lv_std_name);
19
20 end if;
21 fetch cursor_grade into lv_grade_row;
22
Explanation:
Answer:
Assuming this is Python, I would do something like the following:
Explanation:
hourWage= float(input ("What is your hourly wage?: "))
regularHours= float(input ("How many regular hours did you work this week?: "))
overtimeHours= float(input ("How many overtime hours did you have this week?: "))
overtimeWage= (1.5*hourWage)
totalWeeklyPay= (hourWage*regularHours)+(overtimeHours*overtimeWage)
print= ("Your total weekly pay is: " ,totalWeeklyPay)
I hope this works!
