Answer:
6.83 units
Step-by-step explanation:
Let the height of the original pyramid be represented by h. Then the cut off top has a height of (h -2). The scale factor for the area is the square of the scale factor for height, so we have ...
(height ratio)^2 = 1/2
((h -2)/h)^2 = 1/2
(h -2)√2 = h . . . . . . square root; multiply by h√2
h(√2 -1) = 2√2 . . . . add 2√2 -h
h = (2√2)/(√2 -1) ≈ 6.8284 . . . units
The altitude of the original pyramid is about 6.83 units.
Answer: B. 2.5 in
Step-by-step explanation:
From the given right angle triangle,
the hypotenuse of the right angle triangle is the unknown side.
With m∠32 as the reference angle,
the adjacent side of the right angle triangle is 4 in
the opposite side of the right angle triangle is w
To determine w, we would apply
the tangent trigonometric ratio which is expressed as
Tan θ = opposite side/adjacent side. Therefore,
Tan 32 = w/4
w = 4tan32 = 4 × 0.625
w = 2.5 in
Answer:
13
Step-by-step explanation:
a pair=2
so 25/each pair of towns
25/2=12+1=13
