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2 years ago

4(7/8)+7(3/4+1/8)-10 what’s the answer to this? It’s pretty tough ;-;

Mathematics

1 answer:

NISA [10]2 years ago

6 0

Hopes this helps:

Answer: -3/8

Have a great day.

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Which answer shows line segments that are perpendicular to each other? Two parallel line segments with parallel symbol, no arrow

velikii [3]

Two intersecting line segments forming an angle marked with a small box.

The "small box" represents 90°, and perpendicular lines are 2 intersecting lines that form 90° angles

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3 years ago

What is x2+y2−10x+6y+18=0

omeli [17]

Answer:

Step-by-step explanation:

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2 years ago

Find the two inequalities that define the region on the grid that is not shaded

hoa [83]

Answer:

y 》 2

y > -x + 3

Step-by-step explanation:

Equation of the bold line:

m = (-3/3) = -1

y = -x + 3

Shaded region is below y=2 (dotted)

So, it's defined by y < 2

Also, it's below the bold line

y 《 - x + 3

Everything outside these is not shaded:

y 》2

and y > -x + 3

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3 years ago

In a survey, 36% of the students said that they kept an electronic diary. There were 900 students who kept an electronic diary.

Rasek [7]

The answer is 25000.

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2 years ago

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a

kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented $h(t)=-16t^2+20t$ .

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{6}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{2\cdot 6}{1}$

$\text{Average rate of change}=12$

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0

2 years ago