Answer:44.61 KJ
Explanation:
Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system
and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system
mass(m)=7kg
Applying Steady Flow Energy Equation
+Q=
+W




substituting values
=
+W
W=
+Q
W=
+
W=44.61KJ
Complete Question
Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these devises are available for weekend warriors who want to play with their chain saws. Let us model the illustrated tongs as a planar mechanism that carries a log of weight 210 N. Given the following dimensions: 35 mm 10 mm 40 mm 230 mm 85 mm 45 mm 10 mm 35 mm 345 mm determine the force in N and moment in Nm that our worker exerts on the tongs. Also determine the pinching force magnitude in N that the tongs exert on the log; i.e. determine the horizontal force that the tong's teeth exert on the log. Assume the point E is centered between the tong's teeth.
The diagram for this question is shown on the first uploaded image
Answer:
The force P is
and the moment M is 
The horizontal force that the tong teeth exerts is 
Explanation:
First let denote the dimension to corresponding to the diagram

Next looking at the diagram let us consider the vertical direction
At equilibrium

This mean that

Since they are acting in opposite direction the equation becomes

=>
=> 
At Equilibrium Moment about F gives

=> 
=> 
=> 
=> 
Here
is the horizontal force that the tong teeth exerts
Now let consider the part BAF of the system as shown on the second uploaded image
Now the angle
is mathematically given as

=> 


Now at equilibrium the moment about A is

=> 


=> 
=> 
=> 
Looking at the forces acting on the teeth as shown on the third uploaded image
At Equilibrium the moment about D is

=> 
=> 
=> 
=> 
Answer:
I'm good at drawing and computer-animated design
Explanation:
Answer:
The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.
Explanation:
The code is in the image.