Answe whats the question i can help you
Explanation:
a computer used primarily by large organizations for critical applications like bulk data processing for tasks such as censuses, industry and consumer statistics, enterprise resource planning, and large-scale transaction processing
Answer:
2.9*10^14 electrons
Explanation:
An Ampere is the flow of one Coulomb per second, so 35 μA = is 35*10^-6 C per second.
An electron has a charge of 1.6*10^-19 C.
35*10^-6 / 1.6*10^-19 = 2.9*10^14 electrons
So, with a current o 35 μA you have an aevrage of 2.9*10^14 electrons flowing past a fixed reference cross section perpendicular to the direction of flow.
Answer: hello attached below is the properly written chain reaction to your question
answer :
d[NO] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20%2B%20K_%7B3f%7D%5BN%5D%5BOH%5D)
d[N] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20-%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Explanation:
<u>write out expressions for d[NO] / dt and d[N] / dt</u>
Given :
properly written chain reaction ( attached below)
Expression for d[NO] / dt can be written as
Expression for d[N] / dt can be written as
