Answer:
11/4 seconds
Step-by-step explanation:
We can see from the given equation that the height at the diving board is h = 3.
This is because the h(t) equation has that +3 at the end, which denotes the initial height of the diver, the height when he is standing on the board before jumping.
To find where h(t) = 3 is true, we need to set h(t) equal to 3 and solve for t.
h(t) = 3
h(t) = -4t^2 + 11t + 3 = 3
-4t^2 + 11t + 3 - 3 = 0
-4t^2 + 11t = 0
t*(-4t + 11) = 0
so h(t) = 3 when t = 0 and when t = 11/4 sec
we already know that at t = 0 the height is 3, it is the initial height given from the equation, so we want to use the other solution for t.
the diver is back at the height of the diving board at t = 11/4 sec
The value of x is less than or equal to 2.25.
<h2>Linear system</h2>
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
<h3>Simplification</h3>
Simplification is to make something easier to do or understand and to make something less complicated.
Given
The expression is 47.75 + x ≤ 50.
<h3>To find</h3>
The value of x.
<h3>How to find the value of x?</h3>
The expression is 47.75 + x ≤ 50.
On simplifying,
47.75 + x ≤ 50
x ≤ 50 - 47.75
x ≤ 2.25
Thus, the value of x is less than or equal to 2.25.
More about the linear system link is given below.
brainly.com/question/20379472
Answer:
2(x + y)² - 9( x + y ) -5 = 0
⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0
⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0
taking (x + y -5 ) common ,
⇒(x + y -5 )[2(x + y) + 1] =0
⇒(x + y -5)(2x + 2y +1) =0
hope , you got this
Answer:
C)A is 15.95% ,B is 11.85%
Step-by-step explanation:
We know that the expected value in probability distribution is given as
Lets X is the expected value then
For stock A
X=0.25 x 0.45+0.14 x 0.25+0.04 x 0.3
X=0.1595
So the expected return for A is 15.95%
For stock 9
X=0.3 x 0.3+0.09 x 0.25+0.02 x 0.3
X=0.1185
So the expected return for B is 11.85%
So our option C will be the answer of that problem.
