<h3>The worth after 4 years is $ 680.24</h3>
<em><u>Solution:</u></em>
<em><u>The formula for compound interest, including principal sum, is:</u></em>
![A = p(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20p%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Where,
A = the future value of the investment
P = the principal investment amount
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested
From given,
n = 1 ( since interest is compounded annually)
p = 500
t = 4
![r = 8 \% = \frac{8}{100} = 0.08](https://tex.z-dn.net/?f=r%20%3D%208%20%5C%25%20%3D%20%5Cfrac%7B8%7D%7B100%7D%20%3D%200.08)
<em><u>Substituting the values we get,</u></em>
![A = 500(1+ \frac{0.08}{1})^{1 \times 4}\\\\A = 500(1.08)^4\\\\A = 500 \times 1.36048896\\\\A = 680.24448 \approx 680.24](https://tex.z-dn.net/?f=A%20%3D%20500%281%2B%20%5Cfrac%7B0.08%7D%7B1%7D%29%5E%7B1%20%5Ctimes%204%7D%5C%5C%5C%5CA%20%3D%20500%281.08%29%5E4%5C%5C%5C%5CA%20%3D%20500%20%5Ctimes%201.36048896%5C%5C%5C%5CA%20%3D%20680.24448%20%5Capprox%20680.24)
Thus the worth after 4 years is $ 680.24