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3 years ago

What is the volume of a sphere with a radius of 49.5 in, rounded to the nearest tenth of a cubic inch?

Mathematics

1 answer:

NeX [460]3 years ago

6 0

Answer:

Below

Step-by-step explanation:

To find the volume of a sphere you can use this formula!

V = 4/3πr^3

Plugging in the values....

V = 4/3π(49.5)^3

V = 5.08047 × 10^5

V = 5.1 x 10^5 in^3

If you wanted to write this is standard form it would be

V = 508047 in^3

Hope this helps!

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Samantha is buying carpet for her family room, which is 10 yards by 13 yards. the carpeting is sold in square meters. how many

Illusion [34]

1 yard ≈ 0.9144 m

Therefore,
10 yards = 10*0.9144 m = 9.144 m
13 yards = 13*0.9144 m = 11.8872 m

Area to be covered = 9.144*11.8872 = 108.697 m^2

Therefore, Samantha will require approximately 109 m^2 of carpet.

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3 years ago

Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)

zloy xaker [14]

Answer:

$k=0$

$\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}$

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Step-by-step explanation:

We are given the function:

$\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}$

Given that h(1) = 20, we want to find k.

h(1) = 20 means that h(x) = 20 when x = 1. Substitute:

$\displaystyle (20) = 20e^{k(1)}$

Simplify:

$1= e^k$

Anything raised to zero (except for zero) is one. Therefore:

$k=0$

Given that h(1) = 40, we want to find 2k + 1.

Likewise, this means that h(x) = 40 when x = 1. Substitute:

$\displaystyle (40) = 20e^{k(1)}$

Simplify:

$\displaystyle 2 = e^{k}$

We can take the natural log of both sides:

$\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}$

By definition, ln(e) = 1. Hence:

$\displaystyle k = \ln 2$

Therefore:

$2k+1 = 2\ln 2+ 1 \approx 2.3863$

Given that h(1) = 10, we want to find k - 3.

Again, this meas that h(x) = 10 when x = 1. Substitute:

$\displaystyle (10) = 20e^{k(1)}$

Simplfy:

$\displaystyle \frac{1}{2} = e^k$

Take the natural log of both sides:

$\displaystyle \ln \frac{1}{2} = k\ln e$

Therefore:

$\displaystyle k = \ln \frac{1}{2}$

Therefore:

$\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931$

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Hunter-Best [27]

Answer:

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Step-by-step explanation:

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For this case, the first thing we must do is define variables.
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stich3 [128]

Answer:

Step-by-step explanation:

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