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a_sh-v [17]
3 years ago
11

If 2160= 2^a3^b5^c the solution set of a,b,c is{4,3,0}{1,0,3}{4,3,1}{2,3,4}​

Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

4,3,1

Step-by-step explanation:

2^a3^b5^c=2160

2^a3^b5^c=2^4 3^3 5^1

a=4,b=3 and c=1

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