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3 years ago

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If 2160= 2^a3^b5^c the solution set of a,b,c is{4,3,0}{1,0,3}{4,3,1}{2,3,4}

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

4,3,1

Step-by-step explanation:

2^a3^b5^c=2160

2^a3^b5^c=2^4 3^3 5^1

a=4,b=3 and c=1

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Does (10,1) make the inequality 13x+15y greater than or Equal to 19 true?

12345 [234]

Answer:

Yes

Step-by-step explanation:

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3 years ago

{(4z-7,z-4,z) |z is any real number} z=-5

weeeeeb [17]

The set when z = -5 is {-27, -9, -5}

<h3>How to determine the set elements?</h3>

The set is given as:

{(4z-7,z-4,z) |z is any real number}

When z=-5, we have:

4z - 7 = 4(-5) - 7 = -27

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So, we have:

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Hence, the set when z = -5 is {-27, -9, -5}

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brainly.com/question/8053622

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2 years ago

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lawyer [7]

Answer:

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Step-by-step explanation:

You can use proportions to answer this question.

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Step-by-step explanation:

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