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3 years ago

Can anyone help me on question 2?

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

Sure, I can help you with question 2.

Step-by-step explanation:

Original equation:

-3x-7y=2

Substitute x and y values

-3(4)-7(-2)=2

-12+14=2

2=2

This is true, thus (4, -2) <em>is </em>a solution to the given equation.

Katena32 [7]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

-3x - 7y =2

Substitute the point into the equation

-3(4) -7(-2) =2

-12 +14=2

2=2

This is true so the point is a solution to the equation

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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

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A group of students and workers entering a metro station were asked whether they were riding the bus or the subway. the two-way

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The addition of the row and column shows that the number of people polled will be 166.

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Also, it's important to add the row. This will be:

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Step-by-step explanation:

this is not an isoceles triangle.

anyway, we need to remember 2 things :

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3 years ago

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If the store decreases its prices by 20%, then ur actually paying 80%

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lets check..
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