You're assuming that this data set represents all of Mrs. Hassaan's pupils. Certain students could be missing from the histogram - for instance, there could be one or two students who missed the test, but for certain reasons will be taking a make-up exam. Their grade would not be recording in this data set, but they still contribute to the class size, and so would be unaccounted for here.
Answer:
56 chewable tablets
280mL liquid Benadryl
Step-by-step explanation:
For the first part:
First we need to find out how many tablets of 12.5mg would we need per dose.
1 dose is 25 mg and the tablets are in 12.5 mg form.

That would mean you would need 2 tablets per dose.
Next you need to calculate how many times a day it needs to be taken. A day has 24 hours and it needs to be taken every 6 hours. Just divide 24 hours by 6 hours. So that would mean that it needs to be taken 4 times a day.
Next we need to see how many times a week it should be taken and you can get that by multiplying the number of times a day by the number of days a week.
4 x 7 = 28 times
Lastly, you multiply the number of times a week by the number of tablets per dose.
28 times a week x 2 tablets = 56 tablets.
For the second part:
12.5 mg/5mL
The needed dose is 25 mg so we need to find how many mL is needed for 25 mg. 12.5mg is only have of 25 mg we need to double it to attain the correct dosage.
x
= 
This means that for every 25 mg, you will need to give 10mL.
Again we do the same procedure as the first to decide how much liquid Benadryl you need to give in a week. We know that based on the previous that we need to administer this 28 times a week, so just multiply the number of mL per dose by the number of times per week.
10mL x 28 = 280mL
Answer:28.50
I’m doing a lesson for iready and I had the same question
Area inside the semi-circle and outside the triangle is (91.125π - 120) in²
Solution:
Base of the triangle = 10 in
Height of the triangle = 24 in
Area of the triangle = 

Area of the triangle = 120 in²
Using Pythagoras theorem,




Taking square root on both sides, we get
Hypotenuse = 23 inch = diameter
Radius = 23 ÷ 2 = 11.5 in
Area of the semi-circle = 

Area of the semi-circle = 91.125π in²
Area of the shaded portion = (91.125π - 120) in²
Area inside the semi-circle and outside the triangle is (91.125π - 120) in².