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lianna [129]
3 years ago
6

In the reaction 2H2 + O2 + H20, what coefficient should be placed in front of H2O to balance the reaction? 0 2 03 O 4​

Chemistry
1 answer:
guapka [62]3 years ago
6 0

Answer:

2

Explanation:

2×2

2O

soooo

2H2O means 4H2O

You might be interested in
Which technology would be the most useful in predicting an eruption from an undersea volcano and why
sveticcg [70]

Answer: Infrasound because sound waves travel easily through water to accessible buoys.

Explanation: its installation: underwater microphones hung from buoys near a volcano. how it works: senses low-frequency sound waves near a volcano. Since in its installation it specifies that it has UNDERWATER microphones and the question asks in predicting an eruption from an UNDERSEA volcano, that makes perfect sense.

8 0
4 years ago
If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at a constant temperature. What is the new volume​
wel

Answer :

=748

⋅22.5

725

=23.2L

3 0
4 years ago
The mineral benitoite is a gemstone for making jewelry. It has a molecular weight of 413.44 grams/mole and a percent composition
Mila [183]
<h3>Answer:</h3>

               Option-A (BaTiSi₃O₉)

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of Ba  =  %Ba ÷ At.Mass of Ba

                      Moles of Ba  = 33.21 ÷ 137.33

                      Moles of Ba  =  0.241 mol


                      Moles of Ti  =  %Ti ÷ At.Mass of Ti

                      Moles of Ti  = 11.58 ÷ 47.88

                      Moles of Ti  =   0.241 mol


                      Moles of Si  =  %Si ÷ At.Mass of Si

                      Moles of Si  = 20.38 ÷ 28.09

                      Moles of Si  =  0.725 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 34.83 ÷ 16.0

                      Moles of O  =  2.176 mol

Step 2: Find out mole ratio and simplify it;

       Ba                            Ti                                Si                          O

     0.241                       0.241                          0.725                    2.176

 0.241/0.241           0.241/0.241                0.725/0.241            2.176/0.241

         1                             1                                    3                           9 

Hence,  Empirical Formula  =  BaTiSi₃O₉

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  413.44 g.mol⁻¹

Empirical Formula Weight  =  137.33 (Ba) + 47.88(Ti) + 28.09 (Si₃) + 16 (O₉)  =  413.48 g.mol⁻¹

So,

                     n  =  413.44 g.mol⁻¹ ÷ 413.48 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × BaTiSi₃O₉

                   Molecular Formula  =  BaTiSi₃O₉

6 0
4 years ago
22 Which of the following statements is true for all loving organisms? A. All living organisms are made of one or more cells wit
Klio2033 [76]
The answer is C. No all cells have cell walls. Prokaryotes don’t have a nucleus or chloroplast. Leaving C to be correct
8 0
3 years ago
Read 2 more answers
At 35°C, K = 1.6 × 10^-5 for the reaction
TEA [102]

Answer:

a) [NOCl] = 0.968 M

[NO] = 0.032M

[Cl²] = 0.016M

b) [NOCl] = 1.992M

[NO] = 0.008 M

[Cl2]  = 1.004 M

Explanation:

Step 1: Data given

Temperature = 35°C = 308K

K = 1.6 × 10^-5

Step 2: The reaction

2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)

For 2 moles NOCl we'll have 2 moles NO and 1 mol Cl2

Step 3

a. 2.0 mol pure NOCl in a 2.0 L flask

Concentration at the start:

Concentration = mol / volume

[NOCl] = mol / volume

[NOCl] = 2.0 / 2.0 L

[NOCl] = 1.0 M

[NO] = 0 M

[Cl] = 0M

Concentration at the equillibrium

[NOCl] = 1.0M - 2x

[NO] = 2x

[Cl2]= x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6*10^-5 = ((2x)² * x) / (1.0-2x)²

x = 0.016

[NOCl] = 1.0 -  2*0.016 = 0.968 M

[NO] = 2*0.016 = 0.032M

[Cl²] = 0.016M

b. 2.0 mol NOCl and 1.0 mol Cl2 in a 1.0 L flask

Concentration at the equillibrium

[NOCl] = 2.0 mol / 1.0 L = 2.0 M

[NO] = 0 M

[Cl2]= 1.0 mol / 1.0 L = 1.0 M

Concentration at the equillibrium

[NOCl] = 2.0M - 2x

[NO] = 2x

[Cl2]= 1.0 + x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6 *10^-5 = (2x)²*(1.0+x) / ((2.0-2x)²)

1.6 *10^-5= (2x)² * 1 )/2.0²

1.6 *10^-5= 4x² / 4 = x²

x = \sqrt{1.6 *10^-5} = 4.0*10^-3

[NOCl] = 2.0 - 2*0.004 = 1.992M

[NO] = 2*0.004 = 0.008 M

[Cl2] = 1+ 0.004M = 1.004 M

5 0
3 years ago
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