Question

A balloon is filled with 30L of helium gas at 1atm.What is the volume when balloon rises to an attitude where the pressure is only 0.25 atm?

Answer 1

Answer:

$V_2=120L$

Explanation:

Hello!

In this case, since Helium is undergoing a volume-pressure change, according the Boyle's law, we infer the following equation is used:

$P_1V_1=P_2V_2$

Thus, since we are not given the volume at 0.25 atm, we can solve for V2 to do so:

$V_2=\frac{P_1V_1}{P_2}$

Thus, we plug in to obtain:

$V_2=\frac{1atm*30L}{0.25atm}=120L$

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