So,
Let's draw the structures for the following hydrocarbons:
Cyclohexane
We can draw it using the fact that it is a cycloalkane with six carbons:
Cyclohexene
It also contains six carbons with a hexagonal form, but the difference is that there's double bond on it:
Benzene
It has six carbons but there's an alternating double bond as follows:
Toluene
It has the same structure as benzene but it is bonded to a methyl group outside the benzene:
Kp/Kc = RT
<h3>Further explanation</h3>Given
Reaction
A(g) ⇌ C(g)+B(g)
Required
Kp/Kc
Solution
For reaction :
pA + qB ⇒ mC + nD
While the equilibrium constant Kp is based on the partial pressure
The value of Kp and Kc can be linked to the formula '
R = gas constant = 0.0821 L.atm / mol.K
Δn=moles products - moles reactants or
number of product coefficients-number of reactant coefficients
For reaction :
A(g) ⇌ C(g)+B(g)
number of product coefficients = 1+1=2
number of reactant coefficients = 1
Δn= 2 - 1 =1
So Kp/Kc = RT