<span>On the periodic table, the majority of elements are classified as "Metals"
In short, Your Answer would be Option A
Hope this helps!</span>
Answer:
In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.
Explanation:
![Fe(s) + 2HCl(aq)\rightarrow FeCl_2(aq) + H_2(g) ](https://tex.z-dn.net/?f=Fe%28s%29%20%2B%202HCl%28aq%29%5Crightarrow%20%20FeCl_2%28aq%29%20%2B%20H_2%28g%29%0A)
Moles of HCl = n
Molarity of HCl = 1.0M
Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)
![Moles=Molarity\times Volume (L)](https://tex.z-dn.net/?f=Moles%3DMolarity%5Ctimes%20Volume%20%28L%29)
![n=1.0M\times 0.030 L=0.030 mol](https://tex.z-dn.net/?f=n%3D1.0M%5Ctimes%200.030%20L%3D0.030%20mol)
Moles of Fe = ![\frac{0.56 g}{56 g/mol}=0.01 mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.56%20g%7D%7B56%20g%2Fmol%7D%3D0.01%20mol)
According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :
of HCl
This means that HCl uis in excess , hence excessive reagent.
Moles of HCl left unreacted :
= 0.030 mol - 0.020 mol = 0.010 mol
But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.
Answer:
Titrations. Because a noticeable pH change occurs near the equivalence point of acid-base titrations, an indicator can be used to signal the end of a titration. When selecting an indicator for acid-base titrations, choose an indicator whose pH range falls within the pH change of the reaction.
Hope it helped!!
So you need to find the volume in L? If so:
Convert the mass of Lithium Bromide into moles by dividing the 100 grams by the molar mass of LiBr, taken from the periodic table
In a solution, moles = (concentration in mole/L) x (volume in L)
We know the moles, we have the concentration in mole/L, now find the volume in L, and you should get 0.288. Plz do the math and check for yourself
<span>Double displacement reaction is your answer.</span>