So,
Let's draw the structures for the following hydrocarbons:
Cyclohexane
We can draw it using the fact that it is a cycloalkane with six carbons:
Cyclohexene
It also contains six carbons with a hexagonal form, but the difference is that there's double bond on it:
Benzene
It has six carbons but there's an alternating double bond as follows:
Toluene
It has the same structure as benzene but it is bonded to a methyl group outside the benzene:
<span>4.6 moles Hg should be the answer. Hope this helps!</span>
Formula : ClO3-
Name: Chlorate
Bond : Single (I think)
What is it : usually a gas
Kp/Kc = RT
<h3>Further explanation</h3>
Given
Reaction
A(g) ⇌ C(g)+B(g)
Required
Kp/Kc
Solution
For reaction :
pA + qB ⇒ mC + nD
![\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKc%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
While the equilibrium constant Kp is based on the partial pressure
![\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKp%20~%20%3D%20~%20%5Cfrac%20%7B%5BpC%5D%20%5E%20m%20%5BpD%5D%20%5E%20n%7D%20%7B%5BpA%5D%20%5E%20p%20%5BpB%5D%20%5E%20q%7D%7D%7D%7D)
The value of Kp and Kc can be linked to the formula '

R = gas constant = 0.0821 L.atm / mol.K
Δn=moles products - moles reactants or
number of product coefficients-number of reactant coefficients
For reaction :
A(g) ⇌ C(g)+B(g)
number of product coefficients = 1+1=2
number of reactant coefficients = 1
Δn= 2 - 1 =1
So Kp/Kc = RT
D. all of the above, although I do find it hard to believe something like flour would have a melting point, I looked up my answer to double check.