Answer:
The number of moles of CH₄ that will remain is 7.5 moles
Explanation:
Complete combustion reaction of oxygen and methane is given as;
CH₄ + 2O₂ → CO₂ + 2H₂O
comparing the number of moles of methane and oxygen in the reaction above, the amount of methane used in the reaction is calculated as follows;
2 moles of O₂ -----------> 1 mole of CH₄
7 moles of O₂ ------------> x moles of CH₄
x = 7 / 2
x = 3.5 moles of CH₄
Total moles of CH₄ in the reactor = 11.0 moles
The number of moles that will remain = 11.0 moles - 3.5 moles
The number of moles that will remain = 7.5 moles
Therefore, the number of moles of CH₄ that will remain is 7.5 moles
Reactants are on the left side of the arrow, while products are on the right
Answer:
no it would be 2.5 mill your welcome
Explanation:
I’m not 100% sure, but I think hydrogen gas is also produced :)
Answer:
Explanation:
In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:
Now we can identify the variables:
If we plug all the values into the equation:
And we solve for 
:
I hope it helps!
