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Oxana [17]
2 years ago
14

22 Which of the following statements is true for all loving organisms? A. All living organisms are made of one or more cells wit

h a cellular membrane and have a cell wall. B. All living organisms are made of one or more cells with a cellular membrane and have a nucleus. C. All living organisms are made of one ore more cells with a cellular membrane and genetic material. D. All living organisms are made of one or more cells with a cellular membrane and have chloroplast​
Chemistry
2 answers:
Klio2033 [76]2 years ago
8 0
The answer is C. No all cells have cell walls. Prokaryotes don’t have a nucleus or chloroplast. Leaving C to be correct
anygoal [31]2 years ago
7 0

Answer:

C

Explanation:

Ape-x

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What 2 things do the planets need to have in order to stay in orbit and rotate?
Degger [83]
Two things plants need to have in order to stay in orbit and rotate is speed and less velocity.
5 0
3 years ago
Kinematics equations are used only by physicists and people who work in
nevsk [136]

Answer:

FALSE

Explanation:

false. kinematics equations are used for many purposes.it is used to drive equations and to find the motion of an object. but it is used more in physics rather than maths.

5 0
2 years ago
Read 2 more answers
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
2 years ago
21. Draw Lewis structure
Veseljchak [2.6K]

Answer:

C contains one N and three I atoms

7 0
2 years ago
In the compound cah2 calcium has an oxidation number of 2+ and hydrogen has an oxidation number of
sesenic [268]

The oxidation number of H is -1.

Sum of the oxidation numbers in each element = charge of the complex

CaH₂ has 1 Ca atom and 2H atoms. The charge of the complex is zero. Let’s say Oxidation number of H is "a".

Then,

<span>    (+2) + 2 x a = 0 </span>

<span>        +2  + 2a  = 0</span>

                  2a = -2

                    a = -1

Hence, the oxidation number of Hydrogen atom in CaH₂ is -1


7 0
2 years ago
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