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3 years ago

14

Ron charges $10 to park a car in his parking lot. He pays $50 per day to rent the lot. If 40 cars park in his lot during the day

, how much does he earn after expenses?

2 answers:

defon3 years ago

8 0

Answer:

<h2>$350</h2>

Step-by-step explanation:

We know that:

Ron charges $10 per car.
He pays $50 per day for the whole lot.
He parks 40 cars per day.

The total cost for the whole lot per day is fixed $50, which is his expense. The total income he receives for the cars is: $10(40) = $400. So, the difference between the total expenses and the total income is:

$400 - $50 = $350

Therefore, Ron has a net profit of $350 after expenses.

jolli1 [7]3 years ago

5 0

From the cars parked in the lot he will earn (40)($10)=$400, but he will need to pay $50 for the rent. Thus his total $ earned will be $400-$50=$350.

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3 years ago

Write an equation of a parabola that passes through the point (2,4) with vertex (-1,-1) in vertex form.

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An applicable equation of a vertical parabola in vertex form is:

y-k = a(x-h)^2

Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,

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2 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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2 years ago

An airline is planning its staffing needs for the next year. If a new route is approved, it will hire 837 new employees. If a n

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Considering a discrete distribution, it is found that the expected number of new employees to be hired by the airline is of 446.16.

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The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

In this problem, considering the situation described in the text, the distribution is given by:

P(X = 837) = 0.37.

P(X = 199) = 0.63.

Hence, the expected value is given by:

E(X) = 0.37(867) + 0.63(199) = 446.16.

More can be learned about discrete distributions at brainly.com/question/24855677

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1 year ago