Question

Plzzzz help (wrong answers will be deleted )...(100 points!!)

Answer 1

$\boxed{\sf \dfrac{a^m}{a^n}=a^{m-n}}$

$\\ \rm\Rrightarrow \dfrac{16x^4-24x^3+3}{4x^2+3}$

• Take 4x^2+3 common out

$\\ \rm\Rrightarrow 4x^2+3\left(\dfrac{4x^2-24x+1}{1}\right)$

$\\ \rm\Rrightarrow \dfrac{4x^2-24x+1}{1}$

$\\ \rm\Rrightarrow 4x^2-24x+1$

Answer 2

Answer:

4x² - 24x + 1

Step-by-step explanation:

$\frac{16x^{4}-24x^{3}+3}{4x^{2}+3}$

~Factor out the denominator and apply quotient rule [ a^b / a^c = a^b-c ]

$4x^{2}+3 (\frac{\frac{16}{4} x^{4-2}-24x^{3-2}+\frac{3}{3} }{1})$

$\frac{4x^{2}-24x+1}{1}$

~Divide everything by 1

$4x^{2} -24x+1$

Best of Luck!