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Ivanshal [37]
3 years ago
14

Michelle and her brothers Sam and Dean are saving money over summer break each week Michelle saves three times as much as Sam Sa

m saves $2 more than dean at the end of 5 weeks the three of them have saved a total of 240 how much money did each person spend
Mathematics
1 answer:
Triss [41]3 years ago
5 0
I believe you want to know how much each of them SAVED.

Let the amount saved by Michelle be x, the amount saved by Sam be y and the amount saved by Dean be z.

From the givens:
x = 3y (Michelle saves 3 times as much as Sam).......eq1
y = 2+z (Sam saves 2$ more than Dean)
z=y-2.........eq 2
x+y+z = 240 (total amount)......eq 3

substitute by equation 1 in 3:
3y+y+z=240
4y+z=240......eq 4

substitute by 2 in 4:
4y+y-2=240
5y=242
y= 48.4$

from 1:
x=3y
x=145.2$

from 2:
z=y-2
z=46.4$
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6 0
2 years ago
Javier and his friends go out to eat. The restaurant they chose automatically adds a 15% gratuity to their food bill since they
siniylev [52]

well, we know that 213.90 includes the 15% gratuity, so if the meal price was say "x", namely that is the 100%, and we add 15% to that, then 100% + 15% = 115%, so 213.90 is really the 115%.

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\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 213.90&115\\ x&100 \end{array}\implies \cfrac{213.9}{x}=\cfrac{115}{100}\implies 21390=115x \\\\\\ \cfrac{21390}{115}=x\implies 186=x


so since we know the meal without the tip is 186 bucks, the tip was then 213.90 - 186 = 27.90.

but they got extra potato wedges with butter and the waitress was wearing her best hat, they added $20 more, so the tip ended  up as 27.90 + 20 = 47.90.

now, if the cost of the meal was $186 and that is the 100%, what is 47.90 off of it in percentage?


\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 186&100\\ 47.90&x \end{array}\implies \cfrac{186}{47.90}=\cfrac{100}{x}\implies 186x=4790 \\\\\\ x=\cfrac{4790}{186}\implies x\approx \stackrel{\%}{25.75}

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Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

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The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

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W =\int\limits^{60}_{30} {15x} \, dx

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W =15\int\limits^{60}_{30} {x} \, dx

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W =15 \frac{x^2}{2}|\limits^{60}_{30}

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Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
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