Question

Two long straight parallel wires seperated by 20cm apart carry current of 20A and 1OA in opposite directions. What is the magnitude of the force on 1m length of the 20A wire

Answer 1

Answer:

Force is 2 × 10^-4 N

Explanation:

${ \bf{F = \frac{ \gamma_{o} I _{1} I _{2} l}{2\pi r} }}$

F is force

I is current

r is separation distance

gamma is a constant

l is wire length

$F = \frac{(4\pi \times {10}^{ - 7}) \times (20) \times (10) \times 1 }{2\pi \times 0.2} \\ \\ F = 2 \times {10}^{ - 4} \: \: newtons$