J = 16 solve for j by simplifying both sides of the equation, then isolating the variable
To solve this all you need to do is do the opposite of multipulcation:
1590/5
Which equal 318. To check you answer do 318×5
I believe you multiply 1 by 6 because there is an invisible 1 infront of that a then you divide 3.14 to the 2 power And you might get your answer
Answer:
![\bold{495\pi} \approx \bold{1555.088 cm^3}](https://tex.z-dn.net/?f=%5Cbold%7B495%5Cpi%7D%20%5Capprox%20%5Cbold%7B1555.088%20cm%5E3%7D)
Step-by-step explanation:
There was no figure but the question is clear
Volume of a cylinder is given by the formula
where r is radius of base of cylinder, h is the height
Volume of a cone is given by ![\bold{\frac{1}{3} \pi r^2 h}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2%20h%7D)
where r is the radius of base of cone, h is the height
The radius of the cylinder =
(diameter) =
(12) = 6cm
Height of cylinder = 15cm
Volume of cylinder ![V_{cyl} = \pi (6)^2 15 = \pi (36)15 = \bold{540\pi}](https://tex.z-dn.net/?f=V_%7Bcyl%7D%20%3D%20%5Cpi%20%286%29%5E2%20%2015%20%3D%20%5Cpi%20%2836%2915%20%3D%20%5Cbold%7B540%5Cpi%7D)
Radius of cone =
(radius of cylinder) =
(6) = 3 cm
Height of cone same as height of cylinder = 15cm
Volume of cone, ![V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 = \frac{1}{3}(9)15\pi = \bold{45\pi}\\](https://tex.z-dn.net/?f=V_%7Bcone%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%20h%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%283%29%5E2%2015%20%3D%20%20%5Cfrac%7B1%7D%7B3%7D%289%2915%5Cpi%20%3D%20%5Cbold%7B45%5Cpi%7D%5C%5C)
Difference is the volume of the remaining solid
![V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}](https://tex.z-dn.net/?f=V_%7Bcyl%7D%20-%20V_%7Bcone%7D%20%3D%20540%5Cpi%20-%2045%5Cpi%20%3D%20%5Cbold%7B495%5Cpi%7D%20%5Capprox%20%5Cbold%7B1555.088%20cm%5E3%7D)