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3 years ago

A school organised a farewell party of 100 students and school managementn decided three types of drinks distribute in the party

Mathematics

1 answer:

dmitriy555 [2]3 years ago

6 0

The answer is

i) - c

ii) - b

iii) - b

iv) - a

v) - d

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the total cost c a painter charges to paint a house depends on the number h of hours its takes to paint the house. this situatio

Ilya [14]

given that

c = 15h + 245

when h = 30.35 , cost c = (15 × 30.35) + 245

= 453.75 + 245 = 698.75

so cost if painter works = 698.75 unit of currency.

4 0

3 years ago

The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?

Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know:

The initial quantity of silicone-32 is 30 g.
The time elapsed is 300 years.
The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

$N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g$

22.38 g of silicone-32 will be present in 300 years.

7 0

3 years ago

Please help out thanksssss yallllllll!!!!!!!!!

Mila [183]

Answer:

okyyyyyyyyyyyyyyyyyy

4 0

2 years ago

Read 2 more answers

How do you simplify that question? For algebra 1.

motikmotik

$\left( \sqrt{x^{-3}} \right)^5 = \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }$

<span>Explanation for the last step:</span>
$\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}$

7 0

3 years ago

What is the value of a in the equation 3a + b = 54, when b = 9?

nasty-shy [4]

In order to do this you have to substitute b with 9 and get 3a+9=54, now subtract 9 from both sides to leave a by itself and get 3a=45, now divide 3 in both sides to leave a by itself and get a=15

Hope this helps

4 0

3 years ago