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Vladimir [108]
3 years ago
15

Làm thế nào để tắt mỗi chất ra khỏi hỗn hợp gồm bột nhôm bột sắt và bột gỗ?

Chemistry
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

Dùng nam chân hút đc bột sắt ra khỏi hỗn hợp

Bột gỗ và bột nhôm thì bột gỗ tan trong nước còn bột nhôm thì không

Explanation:

  • Nice !
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A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
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* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

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Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
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