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daser333 [38]
3 years ago
11

Which essential fatty acid is rarely found to be deficient as it is typically consumed in abundance in the majority of diets?

Chemistry
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

B. Linoleic acid

Explanation:

Linoleic acid was discovered by chance in 1978 by Michael W. Pariza at the University of Wisconsin looking for mutagene formations in meat during cooking. It is called a conjugated linoleic acid (CLA) to a family of several isomers of linoleic acid (at least 13 are known), which are very common in vegetable oils (corn oil, soybean oil, sunflower oil, etc. ) and in animal fat.

The conjugated linoleic acid is formed by several types of fatty acids, all of them different in their chemical structure. CLAs are a “trans” fat that is not harmful to health, but instead is beneficial

Natural Sources of Conjugated Linoleic Acid

The main natural sources of conjugated linoleic acid in food are:

Beef

Butter

cheese

Lamb

Homogenized milk

Yogurt

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When 4.15 grams of silver nitrate is reacted with 1.11 grams of iron(III) chloride, which best represents the amount of silver c
PolarNik [594]

Answer:

The mass of silver chloride produced = 2.202 g

Explanation:

Equation of the reaction is given below

3AgNO₃(aq) + FeCl₃(aq) ----> 3AgCl(s) + Fe(NO₃)₃(aq)

molar mass of AgNO₃ = 170 g/mol

molar mass of FeCl₃ = 233.5 g/mol

molar mass of AgCl = 143.5 g/mol

3 moles of silver nitrate reacts with 1 mole of iron (iii) chloride to give 3 moles of silver nitrate

4.15 grams of AgNO₃ = 4.15/170 = 0.0244 moles of AgNO₃

1.11 grams of FeCl₃ = 1.11/233.5 = 0.0047 moles of FeCl₃

mole ratio of AgNO₃ to FeCl₃ = 0.0244/0.0047 = 5 : 1

therefore, FeCl₃ is the limiting reactant

0.0047 moles of FeCl₃ reacting will produce 0.0047 *  3 moles of AgCl = 0.0141 moles of AgCl

0.0141 moles of AgCl = 0.0141 * 143.5 g of AgCl = 2.02 g of AgCl =

Therefore mass of silver chloride produced = 2.202 g

3 0
3 years ago
Why is an alkali metal element like sodium (Na) so reactive?
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a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
zhannawk [14.2K]
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
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The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!
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