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4 years ago

Which essential fatty acid is rarely found to be deficient as it is typically consumed in abundance in the majority of diets?

Chemistry

1 answer:

Gre4nikov [31]4 years ago

7 0

Answer:

B. Linoleic acid

Explanation:

Linoleic acid was discovered by chance in 1978 by Michael W. Pariza at the University of Wisconsin looking for mutagene formations in meat during cooking. It is called a conjugated linoleic acid (CLA) to a family of several isomers of linoleic acid (at least 13 are known), which are very common in vegetable oils (corn oil, soybean oil, sunflower oil, etc. ) and in animal fat.

The conjugated linoleic acid is formed by several types of fatty acids, all of them different in their chemical structure. CLAs are a “trans” fat that is not harmful to health, but instead is beneficial

Natural Sources of Conjugated Linoleic Acid

The main natural sources of conjugated linoleic acid in food are:

Beef

Butter

cheese

Lamb

Homogenized milk

Yogurt

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24.0 mL of a 0.120 M Ca(OH)2 solution is required to titrate 160 mL of an HCl solution to its equivalence point. Find the moles

Alex787 [66]

The balanced reaction is as follows;
Ca(OH)₂ + 2HCl ---> CaCl₂ + 2H₂O
stoichiometry of Ca(OH)₂ to HCl is 1:2
number of moles of Ca(OH)₂ reacted = 0.120 mol/L x 0.0240 L = 0.00288 mol according to molar ratio of 1:2 number of HCl moles reacted = twice the number of Ca(OH)₂ moles reacted
number of HCl moles reacted = 0.00288 mol x 2 = 0.00576 mol
number of HCl moles in 160 mL - 0.00576 mol
therefore number of HCl moles in 1000 mL - 0.00576 mol / 160 mL x 1000 mL = 0.036 mol
molarity of HCl = 0.036 M

7 0

3 years ago

Read 2 more answers

What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm

lesya [120]

Answer: The mass of sucrose required is 69.08 g

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL (Density of water = 1 g/mL)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

$8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g$

Hence, the mass of sucrose required is 69.08 g

5 0

3 years ago

A sample of nitrogen gas is stored in a 592.2 mL flask at 108 kPa and 10.0°C. The gas is transferred to a 750.0 mL flask at 28.9

vfiekz [6]

According to Gases law, we know,
PV/T = Constant

So, P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9

Substitute their values,

108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa

In short, Your Final Answer would be: 90.97 kPa

Hope this helps!

8 0

4 years ago

One way to represent this equilibrium is: 2 Al(s) 3 Br2(l)2 AlBr3(s) We could also write this reaction three other ways, listed

myrzilka [38]

The question is incomplete, the complete question is;

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is:

Al(s) + 3/2 Br2(l)AlBr3(s)

We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) 2 AlBr3(s) 2 Al(s) + 3 Br2(l)

2) 2 Al(s) + 3 Br2(l) 2 AlBr3(s)

3) AlBr3(s) Al(s) + 3/2 Br2(l)

Answer:

See explanation

Explanation:

We have that; Al(s) + 3/2 Br2(l)AlBr3(s)

So;

Al(s) + 3/2 Br₂(l) = AlBr₃(s)

K = [ AlBr₃] / [ Al] [ Br₂]³/²

K² = [ AlBr₃]² / [ Al ] ² [ Br₂]³

Now;

1) 2 AlBr₃ = 2 Al(s) + 3 Br₂(l) =

K₁ = [ Al ] ² [ Br₂]³ / [ AlBr₃]²

K₁ = ( 1 / K² ) = K⁻²

For the second reaction;

2 ) 2 Al(s) + 3 Br₂(l) = 2 AlBr₃(s)

K₂ = [ AlBr₃ ]² / [ Al ]² [ Br₂ ]³

K₂ = K²

For the third reaction;

3 )

AlBr₃(s) = Al(s) + 3/2 Br₂(l)

K₃ = [ Al ] [ Br₂ ] ³/² / [ AlBr₃ ]

= ( 1 / K ) = K⁻¹

7 0

4 years ago

Below is a short reaction sequence. Provide the structure of the two missing organic compounds.

dimaraw [331]

The product of this reaction is a halohydrin as shown here.

<h3>What are the products?</h3>

We have a reaction that first involves the formation an alkene as the bases are used on the first substrate. The alkene that is thus created is now able to react with the bromine in water.

The first step of the reaction is where the multiple bond is created and this multiple bond is what can now go on to participate in a chemical reaction in the next step of the process of reaction as shown in the image.

Bromine in water is also hat we call bromine water. This bromine water is able to add across a double bond and when that happen we will have a saturated compound. This could also be regarded as halohydrin reaction.

Recall that the first step of the reaction of the alkene with bromine is the formation of a dibromide via the brominium intermediate. This is now followed by reaction with water to form the halohydrin product.

Learn more about organic reaction:brainly.com/question/9585105

#SPJ1

4 0

2 years ago