Which type of weather is expected at the location

78.6 grams of O2 and 67.3 grams of F2 are placed in a container with a volume of 40.6 L. Find the total pressure if the gasses a

saul85 [17]

1) List the known and unknown quantities.

Sample: O2.

Mass: 78.6 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

Sample: F2.

Mass: 67.3 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

2) Find the pressure of O2.

2.1- List the known and unknown quantities.

Sample: O2.

Mass: 78.6 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

2.2- Convert grams of O2 to moles of O2.

The molar mass of O2 is 31.9988 g/mol.

$mol\text{ }O_2=78.6\text{ }g*\frac{1\text{ }mol\text{ }O_2}{31.9988\text{ }g\text{ }O_2}=2.46\text{ }mol\text{ }O_2$

2.3- Set the equation.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

$PV=nRT$

2.4- Plug in the known quantities and solve for P.

$(P)(40.6\text{ }L)=(2.46\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)$

.

$P_{O_2}=\frac{(2.46\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)}{40.6\text{ }L}$ $P_{O_2}=1.57\text{ }atm$

The pressure of O2 is 1.57 atm.

3) Find the pressure of F2.

3.1- List the known and unknown quantities.

Sample: F2.

Mass: 67.3 g.

Volume: 40.6 L.

Temperature: 43.13 ºC = 316.28 K.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

3.2- Convert grams of F2 to moles of F2.

The mmolar mass of F2 is 37.9968 g/mol.

$mol\text{ }F_2=67.3\text{ }g\text{ }F_2*\frac{1\text{ }mol\text{ }F_2}{37.9968\text{ }g\text{ }F_2}=1.77\text{ }mol\text{ }F_2$

3.3- Set the equation.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

$PV=nRT$

3.4- Plug in the known quantities and solve for P.

$(P)(40.6\text{ }L)=(1.77\text{ }mol\text{ }F_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(316.28\text{ }K)$

.

$P_{F_2}=\frac{(1.77molF_2)(0.082057L*atm*K^{-1}*mol^{-1})(316.28K)}{40.6\text{ }L}$ $P_{F_2}=1.13\text{ }atm$

The pressure of F2 is 1.13 atm.

4) The total pressure.

Dalton's law - Partial pressure. This law states that the total pressure of a gas is equal to the sum of the individual partial pressures.

4.1- Set the equation.

$P_T=P_A+P_B$

4.2- Plug in the known quantities.

$P_T=1.57\text{ }atm+1.13\text{ }atm$ $P_T=2.7\text{ }atm$

The total pressure in the container is 2.7 atm.

5 0

1 year ago

How is the rock cycle related to chemistry??

HACTEHA [7]

Answer:

atoms chemical bonded into an orderly structure

Explanation:

3 0

2 years ago

A mass of 2.20 g carbon monoxide is reacted with 4.86 g hydrogen to form methanol.CO(g) + 2 H2(g) → CH3OH(g)The reaction is perf

iogann1982 [59]

Answer:

The partial pressure in mm Hg for each of the species are:

PCO = 0

PH2 = 3874

PCH3OH = 347

The total pressure is 4221

Explanation:

We have to use Ideal gas equation PV = nRT and Partial pressure rule Total Pressure= ∑ Partial pressures.

We have following data:

T= 357K (85+272); nCO=0.078 (2.2/28); nH2 = 2.43 (4.86/2); R=62.36

With equation CO(g) + 2 H2(g) → CH3OH(g) we can calculate the amount of moles the reaction has finished. The limit reagent is CO because is consumed completely and moles CO in flask are 0. According to equation, every CO mol produces one CH3OH mol. That means 0.078 CO moles produces 0.078 CH3OH moles. From Ideal gas equation we have P=nRT/V.

Applying:

PH2=0.87*62.36*357/5=3874

PCH3OH =0.078*62.36*357/5=347

Total P = 3874+347=4221

I hope my answer helps you

7 0

3 years ago

Make a drawing of the particles in an NaCl solution to show why this solution conducts electricity. Make a drawing of the partic

cluponka [151]

Answer:

See the image attached. It is taken from an online chemistry textbook.

See the explanation below.

Explanation:

Sodium chloride consits of sodium cations (positive ions), Na⁺, and chloride anions (negative ions), CL⁻.

Pure sodium chloride is packed in crystals: sodium ions and chloride ions are packed together and the ions are in fixed positions. There are not free electrons that can move. Thus, sodium chloride doesn't conduct electricity, because there are no electrons or ions which are free to move.

In aqueous solution, sodium chloride units dissociates into their ions:

$NaCl\rightarrow Na^++Cl^-$

Those ions are freely to move in the solution, and such they are charge carriers, which conduct the electricity.

As explained above, in solid sodium chloride, the ions cannot move and there is not flow of current.

That is why solid pure salt of NaCl does not conduct electricity and the solutions of NaCl do conduct electricity.

The image attached show both diagrams. In the diagram A, the ions are packed together, showing that they cannot move. In the diagram B, the ions are dissolved in water, showing that they can move and carry the charge, allowing the flow of current.

5 0

3 years ago

What is a neutralisation reaction Thanks you :)

Ronch [10]

Neutralization is a chemical reaction when an acid and a base react with each other in regards of the quantity of each.

8 0

3 years ago