Answer:
D) ["Kathy Bones", "Jill Brewer", "Joe Schnook", "Tom Smith"]
Explanation:
The context of the problem explains a computer program that sorts names in "ascending order" (A to Z) since the ASCII table has capital A start a lower number and it increases from there to capital Z.
Notice how the attached file, which is a portion of the ASCII table, shows that letters after A are also higher in decimal value than the previous letter.
With this in mind, we know that all this program does is sort by last name alphabetical order. From there, just sort the given names using that same criteria, last name alphabetical order, and the correct answer is determined.
<em>Please put "Brainliest" on my answer if it helped you out!</em>
<em>If you want to learn more about this subject, you can search:</em>
<em>- ASCII Table</em>
<em>- Lists in Programming</em>
<em>- Sorting Procedures</em>
Answer:
I will code in JAVA.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
boolean tallEnough;
boolean oldEnough;
Scanner input = new Scanner(System.in);
tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>
oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>
if(tallEnough && oldEnough){
System.out.print(true);
} else {
System.out.print(false);
}
}
}
Explanation:
First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.
In the if-else statement checks if both variables are true, then prints true. Another case prints always false.
Answer:
it is called a dotted half note
Answer:
B.O(1)
Explanation:
When we are implementing ADT stack using linked chain we can pop an entry from the stack having O(1) time complexity because in linked chain we have the head or top pointer in linked chain only.Popping and pushing in stack happens on only one end that is top.So we have move to move top in linked chain to the next and delete prev node.
Answer:
A line of code to create a constant called MAX that will hold the size of an array that can store up to 25 decimal values. Separate each item with 1 space, and end the line with a semi-colon.
Here,
const int MAX = 25;
