Can you guys plz help me
2 answers:
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Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:
The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:
He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:
The standard deviation is 4.87 shots.
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.