Answer:
<em>Answer is</em><em> </em><em>imaginary</em><em> </em><em>root</em><em>s</em>
Step-by-step explanation:

On solving the above mentioned equation we get some imaginary values.
<em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Answer:
-17
Step-by-step explanation:
3 + 4(-5)
= 3-20
= -17
Hope this helps!
<u>ANSWER:
</u>
Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%
<u>SOLUTION:
</u>
Given,
P = RS 2000
C.I = RS 2315.35
T = 3 years
We need to find the rate per annum. i.e. R = ?
We know that,
When interest is compound Annually:

Where p = principal amount
r = rate of interest
n = number of years



![$1+\frac{R}{100}=\sqrt[3]{1.157}$](https://tex.z-dn.net/?f=%241%2B%5Cfrac%7BR%7D%7B100%7D%3D%5Csqrt%5B3%5D%7B1.157%7D%24)



R = 5%
Hence, rate per annum is 5 percent.
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75
Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825
We're now gonna do the same with machine D.
130 x 11 = 1430
Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.
This is how we find our final answer.
Our answer would be D) 605.
Hope this helps!~