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Genrish500 [490]
3 years ago
12

Evaluate. 2 • {390 – [5 • (10 – 4 ÷ 2)] + 15} • 2

Mathematics
1 answer:
otez555 [7]3 years ago
8 0
The correct answer is 1460

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at the pet fair,darlene's dog weighed 5 times as much as leah's dog.together the dog weighed 84 pounds. how much did each dog we
adelina 88 [10]
Darlene's dog weighed 70 pounds. And leah's dog weighed 14 pounds. 
5 0
2 years ago
Let's Apply Solve for the surface area of the following figures. ​<br><br>please i need this rn​
Dafna1 [17]

Answer:

Step-by-step explanation:

1) Surface area of a square = s*s = 12*12 = 144 in

2) Surface area of a Cone =  A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2

3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2

4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2

5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2

3 0
2 years ago
An athlete takes 10 rounds of a rectangular park, 60 m long and 35 m wide. Find the total distance covered by him
serious [3.7K]

Answer:

1900M

Step-by-step explanation:

If the athlete runs round a rectangular park, the distance covered can be determined by calculating the perimeter of the park

Perimeter of a rectangle = 2 x (length + width)

2 x (60 + 35) = 190m

Since he run rounds 10 times, the total distance covered = 190m x 10 = 1900m

5 0
2 years ago
Help Me On This!!<br><br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20" id="TexFormula1" title=" \\ \\
salantis [7]

Answer:

First Find the Radius of Cake by dividing 40/2

Now Find Area of the cake of Bottom

And Then Use the Formula to calculate volume of Circle

Cross Section Area=π Square

Bole of Circle 4/3π× radius cube

8 0
2 years ago
Read 2 more answers
Two possible solutions of are -7 and 1. Which statement is true?
quester [9]

We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.

√11 - 2(-7) = √(-7)^2 + 4(-7) + 4

√25 = √25

5 = 5

The first solution, -7, makes the equation true, and so it is not extraneous.

√11 - 2(1) = √(1)^2 + 4(1) + 4

√9 = √9

3 = 3

The second solution, 1, makes the equation true, and so it is also not extraneous.

<h3>The correct option is D, neither solution is extraneous. </h3>
4 0
2 years ago
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