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2 years ago

How much cost Rs 1136 when it is 10% discount and 13% vat is added then find out the discount and Vat amount

Mathematics

1 answer:

S_A_V [24]2 years ago

7 0

Answer:

Rs 1155.3

Step-by-step explanation:

1136 * .1 = 113.6

1136 - 113.6 = 1022.4

1022.4 * 1.13 = 1155.3

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That would be the area of a circle of radius 12 miles

= pi r^2 = 452.4 square miles to nearest tenth.

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2 years ago

Describe the relationship. Check all that apply.

AlekseyPX

Answer:

this is a negative association

Step-by-step explanation:

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2 years ago

Please help me find the area of the trapezoid

alex41 [277]

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3 years ago

Read 2 more answers

Nathan ordered one cheeseburger and one bag of chips for 3.75 jack ordered two cheeseburgers and three bags of chips for 8.25 kn

Elan Coil [88]

Answer:

cheeseburger is $3 and chips is $0.75

Step-by-step explanation:

Let price of cheeseburger be x while price of a bag of chips be y hence for the case of Nathan, we can write the equation as x+y=3.75. Similarly, for Jack, we can write it as 2x+3y=8.25

x+y=3.75 hence x=3.75-y and substituting this into the second equation we have

2x+3y=8.25

2(3.75-y)+3y=8.25

7.5-2y+3y=8.25

y=8.25-7.5=0.75

x=3.75-y=3.75-0.75=3

Therefore, price of cheeseburger is $3 and chips is $0.75

7 0

2 years ago

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

6 0

2 years ago