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3 years ago

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Pat is required to sell candy bars to raise money for the 6th grade field trip. There is a 40% chance of him selling a candy bar

at each house. He has to sell 5 candy bars in all. Let X be of number of houses it takes a. Name distribution (with parameter(s)) of X. What is the probability he sells his last candy bar at the 11th house

1 answer:

labwork [276]3 years ago

4 0

Answer:

It will take him about 13 houses to sell the 5 candy bars.

Pat has an 18% chance of selling his last candy in the 11th house.

Step-by-step explanation:

Since Pat is required to sell candy bars to raise money for the 6th grade field trip, and there is a 40% chance of him selling a candy bar at each house, and he has to sell 5 candy bars in all, to determine the number of houses it takes and determine the probability he sells his last candy bar at the 11th house, the following calculations must be performed:

5 / 0.40 = X

12.5 = X

So, it will take him about 13 houses to sell the 5 candy bars.

5/11 = X

0.45 = X

0.45 x 0.4 = 0.18

Thus, Pat has an 18% chance of selling his last candy in the 11th house.

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2 years ago

Read 2 more answers

What is the equation of the line parallel to 3x + 5y = 11 that passes through the point (15, 4)?

soldier1979 [14.2K]

Answer:

The answer is

<h2> $y = - \frac{3}{5} x + 13$ </h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is 3x + 5y = 11

We must first write the equation in the general equation above

So we have

5y = - 3x + 11

Divide both sides by 5

<h3> $y = - \frac{ 3}{5} x + \frac{11}{5}$ </h3>

Comparing with the general equation above

Slope = - 3/5

Since the lines are parallel their slope are also the same

Slope of parallel line = - 3/5

So the equation of the line using point

(15, 4) and slope - 3/5 is

<h3> $y - 4 = - \frac{3}{5} (x - 15) \\y - 4 = - \frac{3}{5} x + 9 \\ y = - \frac{3}{5} x + 9 + 4$ </h3>

We have the final answer as

<h3> $y = - \frac{3}{5} x + 13$ </h3>

Hope this helps you

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2 years ago

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aalyn [17]

Answer:

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3 years ago

Find the central angle of a sector of a circle of the area of the sector and the area of the circle are in the proportion of 3:5

abruzzese [7]

Answer:

$\theta = 216$

Step-by-step explanation:

Given

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Required

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$5 * \frac{Area_{sector}}{Area_{circle}} = \frac{3}{5} * 5$

$5 * \frac{Area_{sector}}{Area_{circle}} = 3$

Multiply both sides by Area{circle}

$5 * \frac{Area_{sector}}{Area_{circle}} * Area_{circle} = 3 * Area_{circle}$

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Substitute the areas of sector and circle with their respective formulas;

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So, we have

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Divide both sides by $\pi r^2$

$5 * \frac{\theta}{360} * \frac{ \pi r^2}{\pi r^2} = 3 * \frac{\pi r^2}{\pi r^2}$

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Multiply both sides by 360

$360 * 5 * \frac{\theta}{360} = 3 * 360$

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Divide both sides by 5

$\frac{5 * \theta}{5} = \frac{3 * 360}{5}$

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Hence, the central angle is 216 degrees

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2 years ago