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marin [14]
3 years ago
12

Pat is required to sell candy bars to raise money for the 6th grade field trip. There is a 40% chance of him selling a candy bar

at each house. He has to sell 5 candy bars in all. Let X be of number of houses it takes a. Name distribution (with parameter(s)) of X. What is the probability he sells his last candy bar at the 11th house
Mathematics
1 answer:
labwork [276]3 years ago
4 0

Answer:

It will take him about 13 houses to sell the 5 candy bars.

Pat has an 18% chance of selling his last candy in the 11th house.

Step-by-step explanation:

Since Pat is required to sell candy bars to raise money for the 6th grade field trip, and there is a 40% chance of him selling a candy bar at each house, and he has to sell 5 candy bars in all, to determine the number of houses it takes and determine the probability he sells his last candy bar at the 11th house, the following calculations must be performed:

5 / 0.40 = X

12.5 = X

So, it will take him about 13 houses to sell the 5 candy bars.

5/11 = X

0.45 = X

0.45 x 0.4 = 0.18

Thus, Pat has an 18% chance of selling his last candy in the 11th house.

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3 years ago
A company is manufacturing an open-top rectangular box. They have 30 cm by 16 cm sheets of material. The bins are made by cuttin
Natalija [7]

Answer:

a. (30 - 2x)(16 - 2x)x. b. length 21.2 cm , width = 7.2 cm and height x = 4.4 cm

Step-by-step explanation:

a. Let x be the side of the squares to be cut from each corner. Since we have two corners on each side, the length of the resulting box from the 30 cm by 16 cm sheet is L = 30 - 2x. Its breadth is B = 16 - 2x. The height of the resulting box is x. So its volume V = LBx = (30 - 2x)(16 - 2x)x.

b. To find the maximum value of V, we differentiate V with respect to x and equate it to zero.

So, dV/dx = 0

d(30 - 2x)(16 - 2x)x/dx = 0

-2(16 - 2x)x + (-2)(30 - 2x)x + (30 - 2x)(16 - 2x) = 0

32x + 4x² - 60x - 4x² + 480 - 60x - 32x + 4x² = 0

4x²- 120x + 450 = 0

x²- 30x + 112.5 = 0

Using the quadratic formula, we find x. So, with a = 1, b = - 15 and c = 112.5,

x = \frac{-(-30)+/-\sqrt{(-30)^{2} - 4 X 1 X 112.5} }{2 X 1} \\= \frac{30+/-\sqrt{900 - 450} }{2}\\ = \frac{30+/-\sqrt{450} }{2}\\ = \frac{30+/-21.21 }{2}\\\\ = \frac{30+21.21 }{2}   or  \frac{30-21.21 }{2}\\ = \frac{51.21 }{2}   or  \frac{8.79}{2}\\ = 25.605 or 4.395

x ≅ 25.61 or 4.4

V = (30 - 2x)(16 - 2x)x

Substituting the values of x into L and B, we have )x

L = (30 - 2x) = (30 - 2(25.61)) = 30 - 51.22 = -21.22

B = (16 - 2x) = (16 - 2(25.61)) = 16 - 51.22 = -35.22

Since L and B cannot be negative, we use the other value for x = 4.4, So

L = (30 - 2x) = (30 - 2(4.4)) = 30 - 8.8 = 21.2

B = (16 - 2x) = (16 - 2(4.4)) = 16 - 8.8 = 7.2

So V = LBx = 21.2 × 7.2 × 4.4 = 671.62 cm³

3 0
3 years ago
What is the solution of x-7= ir+14,
weqwewe [10]

Answer:

x=12

Step-by-step explanation:

put the x at one side and the numbers ar the other

5/2x-3/4x=14+7

10/4x-3/4x=21

7/4x=21

7x=84

x=12

3 0
3 years ago
Marisol constructed a triangle. One angle in the triangle has a measure of 40°. Another angle in the triangle has a measure of 8
Tanzania [10]

Answer:

A triangles angle always equal to 180 degrees. So if you add up what you already have which is 80+40=120

5 0
3 years ago
A ramp into a building forms a 6° angle with the ground. If the ramp is 8 feet long, how far away from the building is the entry
Sauron [17]

Answer:

7.96 ft

Step-by-step explanation:

Given;

Length of ramp L = 8 ft

Angle with the horizontal (ground) = 6°

Applying trigonometry;

With the length of ramp as the hypothenuse,

The horizontal distance d as the adjacent to angle 6°

Since we want to calculate the adjacent and we have the hypothenuse and the angle. We can apply cosine;

Cosθ = adjacent/hypothenuse

Substituting the values;

Cos6° = d/8

d = 8cos6°

d = 7.956175162946

d = 7.96 ft

The building is 7.96ft away from the entry point of the ramp.

6 0
3 years ago
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