Question

Pat is required to sell candy bars to raise money for the 6th grade field trip. There is a 40% chance of him selling a candy bar at each house. He has to sell 5 candy bars in all. Let X be of number of houses it takes a. Name distribution (with parameter(s)) of X. What is the probability he sells his last candy bar at the 11th house

Answer 1

Answer:

It will take him about 13 houses to sell the 5 candy bars.

Pat has an 18% chance of selling his last candy in the 11th house.

Step-by-step explanation:

Since Pat is required to sell candy bars to raise money for the 6th grade field trip, and there is a 40% chance of him selling a candy bar at each house, and he has to sell 5 candy bars in all, to determine the number of houses it takes and determine the probability he sells his last candy bar at the 11th house, the following calculations must be performed:

5 / 0.40 = X

12.5 = X

So, it will take him about 13 houses to sell the 5 candy bars.

5/11 = X

0.45 = X

0.45 x 0.4 = 0.18

Thus, Pat has an 18% chance of selling his last candy in the 11th house.