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Talja [164]
2 years ago
13

If 6x=9y find the value of x:y.​

Mathematics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

A complete angle is one which measures 360∘360∘.

The three angles

6x+20∘,9y+30∘,3z+40∘6x+20∘,9y+30∘,3z+40∘

add up to 360∘360∘, as per the question.

6x+20∘+9y+30∘+3z+40∘=360∘6x+20∘+9y+30∘+3z+40∘=360∘

⟹3(2x+3y+z)+90∘=360∘⟹3(2x+3y+z)+90∘=360∘

⟹3(2x+3y+z)=270∘⟹3(2x+3y+z)=270∘

⟹2x+3y+z=90∘⟹2x+3y+z=90∘

This is the required relation.

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Answer:

7.3

Step-by-step explanation:

For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.

Distance = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

X2 is 7 (X coordinate of school)

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2 years ago
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Evaluate.4 2 – 6+2 +3 =
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3 0
1 year ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 &lt; t &lt; 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
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