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Elden [556K]
3 years ago
14

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

Mathematics
2 answers:
stellarik [79]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

-5 ( x - 1 ) -x +1 = -18

solve the brackets first

-5x + 5 - x + 1 = -18

-5x -x +5 +1 = -18

-6x + 6 = -18

-6x  = -18 - 6

-6x = -24

x = -24 / -6

x = 4

kompoz [17]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

-5(x-1)-x+1=-18\\\\-5x+5-x+1=-18\\\\-6x+6=-18\\\\-6x=-24\\\\x=4

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Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
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3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
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4) find n(x) in the interval B,C
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n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
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6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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