An equiangular triangle adds up to 180 so divide that by 3, which is the number of sides, and you get, 60, therefore, each side is 60<span>° angle.</span>
Answer:
x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
or x =~ -1.29399
Step-by-step explanation:
Calculate the product. x^2 * 6x = 6x^3
divide both sides by 6. x^3 = -13/6
Take the root of both sides. x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
Maybe you thought about this:
m^2+6m-77+5=0 => m^2+6m-72=0 => m^2+ 2*3*m+3^2-3^2-72=0
=> m^2+2*3*x+3^2= (m+3)^2 this is the complete square of the binomial, we will still keep it =>
(m+3)^2 -9 -72=0 => (m+3)^2 - 81 = 0 => (m+3)^2 - 9^2 = 0
Now we got the difference squares, it mean a^2 - b^2 = (a-b) (a+b)
In according to this => (m+3-9) (m+3+9) = 0 =>
(m-6) (m+12)=0 => m-6=0 or m+12=0 => m1=6 or m2= -12 !!!!
Are you satisfied with this solution?