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GarryVolchara [31]
3 years ago
13

A flagpole casts a shadow 16 feet long.

Mathematics
1 answer:
Triss [41]3 years ago
7 0

Step-by-step explanation:

Since Shanika is standing near the pole, we can safely assume that the triangle formed by Shanika and her shadow is a smaller version of the triangle formed by the pole and its shadow.

By similar triangles:

\frac{x \: of \: pole}{y \: of \: pole}  =  \frac{x \: of \: shanika}{y \: of \: shanika}  \\  \frac{16}{ height \: of \: pole}  =  \frac{4}{5}  \\ 16(5) = 4 \times height \: of \: pole \\  height \: of \: pole =  \frac{80}{4}  \\  = 20

The height of the pole is 20ft.

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qaws [65]

36 cm^2

Step-by-step explanation:

<u>Small</u><u> </u><u>window</u>

Length: 2cm

Width: 2cm

<u>Area</u><u>:</u> 4 cm^2

<u>Big window</u>

Length: 4cm

Width: 3cm

<u>Area</u><u>:</u> 12 cm^2

Total area of the windows:

(Area of 4 small windows + area of 1 big window)

(4 cm^2 x 4 + 12cm^2)

= <u>28 cm^2</u>

<u>Above</u><u> </u><u>window</u><u> </u><u>(</u><u>approx</u><u>.</u><u>)</u>

<u>Rectangle</u>

Length: 3cm

Width: 2cm

<u>Area</u><u>:</u> 6 cm^2

<u>T</u><u>riangle</u>

Base: 1cm

Height: 1cm

<u>Area</u><u>:</u> 2 x 0.5 cm^2 = 1 cm^2

<u>Square</u><u> </u><u>(</u><u>between</u><u> </u><u>the</u><u> </u><u>triangles</u><u>)</u>

Length: 1cm

Width: 1cm

<u>Area</u><u>:</u> 1 cm^2

= 8 cm^2

<u>TOTAL</u><u> </u><u>AREA</u><u> </u><u>OF</u><u> </u><u>ALL</u><u> </u><u>WINDOWS</u>

= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW

= 16 cm^2 + 12 cm^2 + 8 cm^2

<h3>= <u>36 cm^2</u></h3>

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