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antoniya [11.8K]
3 years ago
14

Math experts ONCE AGAIN :) giving brainly!!

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Answer:

A) $49

Step-by-step explanation:

There are two ways to solve this problem. You could either calculate the net change by adding up the values in the table and then adding that to the initial amount, or you could individually add every change in price to the initial amount. I'm going to go with the first way, as I find it to be quicker, but both methods work equally well.

We know that the stock was worth $52 on Monday morning. From the table, the net (or overall) change in the stock over the course of the week is:

-2 + 1 + 3 - 1 - 4 = -3

Therefore, the stock's price decreased by $3 over the week, and because the stock's original price was $52, we know it is now worth 52 - 3 = $49. Hope this helps!

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-2x + y=9<br> -4x - y=9 <br> What is the answer
Dmitry_Shevchenko [17]

-2x + y = 9

-4x - y = 9

----------------- +

-6x = 18

x = -3

-2x + y = 9

-2(-3) + y = 9

6 + y = 9

y = 3

3 0
3 years ago
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Jacob solves the system of equations by forming a matrix equation.
Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

We have:

4x + y = 2

-2x + 4y = -22

Calculate the determinant of \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

|A| = 4 \times 3 -1 \times -2

|A| = 12 +2

|A| = 14

So, the inverse matrix becomes

A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

Replace the first column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of x

x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]

So, we have:

x = \frac{1}{14}(2 \times 3 - 1 \times -22)

x = \frac{1}{14}(6 +22)

x = \frac{1}{14}(28)

x = 2

Replace the second column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of y

y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]

So, we have:

y = \frac{1}{14}(4 \times -22 - 2 \times -2)

y = \frac{1}{14}(-88 +4)

y = \frac{1}{14}(-84)

y = -6

Hence, the complete process is:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

Read more about matrices at:

brainly.com/question/11367104

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3 years ago
What is answer? A,b,c,d
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The answer to your question is D.
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Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
kenny6666 [7]
Hello:
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y' (1/2) +(π/3)(√3/2) = -  π 

y' (1/2) =-(π/3)(√3/2)  -  π 
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5 0
4 years ago
If $1995.00 is shared equally among 5 men, how much would each get?
Vesna [10]

Answer:

each would receive $399

Step-by-step explanation:

divide 5 from 1995 which equals 399 :)

8 0
3 years ago
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