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Y_Kistochka [10]
2 years ago
5

In part A of the lab we see that the magnetic field of a long straight wire __. a. increases with distance in a linear relations

hip b. increases with distance in a non-linear relationship c. decreases with distance in an inverse (1/r) relationship d. decreases with distance in an inverse-square (1/r2) relationship
Physics
1 answer:
Amanda [17]2 years ago
6 0

Explanation:

a long straight wire __. a. increases with distance in a linear relationship b. increases with distance in a non-linear relationship c. decreases with distance in an inverse (1/r) relationship d. decreases with distance in an inverse-square (1/r2) relationship

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Would You Rather...Carry a 50 lb box up 3 flights of stairs or a 25 lb box up 5 flights of stairs? Whichever choice you make, ju
Oksanka [162]

I would carry a 25 pound box up 5 flights, because it is lighter. You will wear out faster carrying a 50 pound box up 3 flights.

8 0
3 years ago
Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward
stich3 [128]
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m

4 0
3 years ago
Consider a large 1.54 V carbon-zinc dry cell used in a physics lab to supply 2.15 A to a circuit. The internal resistance of the
andrew-mc [135]
<h2>Answer:</h2>

1.77V

<h2>Explanation:</h2>

The electromotive force voltage (E) in a cell, is related to the lost voltage (V_{L}) and the terminal voltage (V_{T}) as follows;

E = V_{T} - V_{L}

Where;

The lost voltage (V_{L}) is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e

V_{L} =  I x r

<em>Substitute </em>V_{L}<em> =  I x r into equation (i) as follows;</em>

E = V_{T} - (I x r)           ----------------------(ii)

<em>According to the question;</em>

E = 1.54V

I = 2.15A

r = 0.105Ω

<em>Substitute these values into equation(ii) as follows;</em>

1.54 = V_{T} - (2.15 x 0.105)

1.54 = V_{T} - (0.22575)

1.54 = V_{T} - 0.22575

<em>Solve for </em>V_{T}<em>;</em>

V_{T} = 1.54 + 0.22575

V_{T} = 1.54 + 0.22575

V_{T} = 1.77V

Therefore, the terminal voltage of the cell is 1.77V

8 0
3 years ago
Why does the emission spectrum of hydrogen or unknown source have a distinct line spectrum instead of a continuous one?
aleksandr82 [10.1K]

Answer

When an electron makes transition from a state of higher energy to a state of lower energy it does so by emitting energy in form of radiation in the visible spectrum of light.

Since the basic postulates of the atomic theory is that the energy that the electron possess in it's orbit's takes only discrete values and cannot take any random value thus when an electron makes a transition from a state of higher energy to state of lower energy it will emit radiation with energy equal to difference between the energy levels of the 2 orbit's thus we only observe discrete lines.

Mathematically when an electron makes a transition between states the wavelength of light it releases is given by

\frac{1}{\lambda }=R_{\infty }(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}})

where R_{\infty } is Rydberg constant

n_{1} is upper energy level

n_{2} is lower energy level

thus we can see that only discrete wavelength's are released and not continuous wavelength's of light.

3 0
3 years ago
How come that there is a presence of cos there?
liubo4ka [24]

Answer:

Can i have more context

Explanation:

8 0
3 years ago
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