You know the following:
k= 25N/m
x=1.5m
Now you just plug these numbers into the formula which is
Epe = 1/2kx²
= 1/2(25N/m)(1.5m)²
= 28.125J or in proper sigdigs 28J
Hope this helps!
Answer:
The moment of inertia of large ring is 2MR².
(A) is correct option.
Explanation:
Given that,
Mass of ring = M
Radius of ring = R
Moment of inertia of a thin ring = MR²
Moment of inertia :
Moment of inertia is the product of the mass of the ring and square of radius of the ring.
We need to calculate the moment of inertia of large ring
Using formula of moment of inertia

Where,
= moment of inertia at center of mass
M = mass of ring
R = radius of ring
Put the value into the formula


Hence, The moment of inertia of large ring is 2MR².
Answer:
the cell is the smallest unit
<span>the majority party................</span>
C.
because centripetal means that force only acts in the center of body in motion