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3 years ago

Differences Between light year and astronomical unit in two points .

1 answer:

5 0

One astronomical unit (AU) is the average distance from the Earth to the Sun, which is about 93-million miles or about 8.5 light-minutes.

A light-year is the distance light travels in one year in a vacuum, which is about 6-trillion miles. One light-year is about 64,500 times longer than one AU.

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In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result

raketka [301]

According to the given statement:

The frequency response does not change, which is the first thing we notice.

The new resistance at the resonance point causes a reduction in the circuit's current flow.
Z = R + R₂

<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

Z₀² = R² + (X $_L$ -X $_C$ ) ²

The initial resistance impedance shifts to when we add another resistor to the series

Z² = (R + R₂) ² + (X $_L$ - X $_C$ ) ²

Let's examine this sentence.

The frequency response remains unchanged, which is the first thing we notice.
The new resistance at the resonance point causes the circuit's current to decrease.

Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

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6 0

1 year ago

How is energy transferred throughout the roller coaster

solmaris [256]

Answer:

On a roller coaster, energy changes from potential to kinetic and back again many times over and over the course of the ride. Kinetic energy is energy that an object has because of its motion. All moving objects possess kinetic energy, which is determined by the mass and speed of the object.

Explanation:

3 0

3 years ago

Read 2 more answers

A spaceship negotiates a circular turn of radius 2925 km at a speed of 29960 km/h. (a) What is the magnitude of the angular spee

emmainna [20.7K]

a) 0.0028 rad/s

b) $23.68 m/s^2$

c) $0 m/s^2$

Explanation:

When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by

$\omega = \frac{\theta}{t}$

where

$\theta$ is the angular displacement

t is the time interval

The angular speed of an object in circular motion can also be written as

$\omega = \frac{v}{r}$ (1)

where

v is the linear speed of the object

r is the radius of the orbit

For the spaceship in this problem we have:

$v=29,960 km/h$ is the linear speed, converted into m/s,

$v=8322 m/s$

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Subsituting into eq(1), we find the angular speed of the spaceship:

$\omega=\frac{8322}{2.925\cdot 10^6}=0.0028 rad/s$

When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.

The magnitude of the radial acceleration is given by

$a_r=\omega^2 r$

where

$\omega$ is the angular speed

$r$ is the radius of the orbit

For the spaceship in the problem, we have

$\omega=0.0028 rad/s$ is the angular speed

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Substittuing into the equation above, we find the radial acceleration:

$a_r=(0.0028)^2(2.925\cdot 10^6)=23.68 m/s^2$

When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.

The tangential acceleration is given by

$a_t=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in the linear speed

$\Delta t$ is the time interval

In this problem, the spaceship is moving with constant linear speed equal to

$v=8322 m/s$

Therefore, its linear speed is not changing, so the change in linear speed is zero:

$\Delta v=0$

And therefore, the tangential acceleration is zero as well:

$a_t=\frac{0}{\Delta t}=0 m/s^2$

5 0

3 years ago

Which of the following has been identified as one of the seven basic emotions that are present as early as infancy?

Irina-Kira [14]

The answer is c. interest.

4 0

3 years ago

A syringe of volume 16 cm3 is filled with air to a pressure of 1.03 atm. If the piston of the syringe is pushed to change the vo

denpristay [2]

<h3>Answer:</h3>

189.07 kPa

<h3>Explanation:</h3>

Concept tested: Boyle's law

<u>We are given;</u>

Initial volume of the syringe, V1 is 16 cm³
Initial pressure of the syringe, P1 is 1.03 atm
New volume of the syringe, V2 is 8.83 cm³

We are required to calculate the new pressure of the syringe;

We are going to use the concept on Boyle's law of gases.
According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.

That is; P α 1/V

At varying pressure and volume, k(constant) = PV and P1V1=P2V2

Therefore, to get the new pressure, P2, we rearrange the formula;

P2 = P1V1 ÷ V2

= ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³

= 1.866 atm.

Thus, the new pressure is 1.866 atm
But, we need to convert pressure to Kpa
Conversion factor is 101.325 kPa/atm

Thus;

Pressure = 1.866 atm × 101.325 kPa/atm

= 189.07 kPa

Hence, the new pressure of the air in the syringe is 189.07 kPa

3 0

3 years ago