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3 years ago

Let mAngleA = 40°. If AngleB is a complement of AngleA, and AngleC is a supplement of AngleB, find these measures.

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

7 0

Answer:

$m\angle B = 50^\circ$

$m\angle C = 130^\circ$

Step-by-step explanation:

We are given the following information in the question:

$m\angle A = 40^\circ$

Angle B is a complement of Angle A. Thus, we can write:

$\angle A + \angle B = 90^\circ\\\angle B = 90 - m\angle A\\\angle B = 90 - 40 = 50\\m\angle B = 50^\circ$

Angle C is a supplement of Angle B. Thus, we can write:

$\angle C + \angle B = 180^\circ\\\angle C = 180 - m\angle B\\\angle C = 180 - 50 = 130\\m\angle C = 130^\circ$

wlad13 [49]3 years ago

5 0

Answer:

the answer is m angle B = 50

m angle C = 130

Step-by-step explanation:

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Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

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2) For each two values of x, a value of y is increased by 10.

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x = 1, y = $\frac{7}{5}$

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x = 0, y = 2

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Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

$y=5x+5$

When x = 0, y = ?

$y=5(0)+5\\y=0+5\\y=5$

When x = 1, y = ?

$y=5(1)+5\\y=5+5\\y=10$

When x = 2, y = ?

$y=5(2)+5\\y=10+5\\y=15$

When x = 3, y = ?

$y=5(3)+5\\y=15+5\\y=20$

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$y=5x-2$

When x = 0, y = ?

$y=5(0)-2\\y=0-2\\y=-2$

When x = 2, y = ?

$y=5(2)-2\\y=10-2\\y=8$

When x = 4, y = ?

$y=5(4)-2\\y=20-2\\y=18$

When x = 6, y = ?

$y=5(6)-2\\y=30-2\\y=28$

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$y=\frac{2}{5}x +1$

When x = 0, y = ?

$y=\frac{2}{5}(0) +1$

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When x = 1, y = ?

$y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1$

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When x = 5, y = ?

$y=\frac{2}{5}(5) +1\\y=2+1\\y=3$

When x = 10, y = ?

$y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5$

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When x = 0, y = ?

$y=15(0)+2\\y=0+2\\y=2$

When x = 1, y = ?

$y=15(1)+2\\y=15+2\\y=17$

When x = 2, y = ?

$y=15(2)+2\\y=30+2\\y=32$

When x = 5, y = ?

$y=15(5)+2\\y=75+2\\y=77$

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