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Mashutka [201]
3 years ago
6

Is x + 1 a factor of

title="x^{4} +2x^{3} +2x^{2} -2x-3" alt="x^{4} +2x^{3} +2x^{2} -2x-3" align="absmiddle" class="latex-formula">?
Mathematics
2 answers:
JulsSmile [24]3 years ago
4 0
Yes x+1 is a factor of that
Svetllana [295]3 years ago
4 0

Answer:

Yes.

Step-by-step explanation:

We want to determine if (<em>x</em> + 1) is a factor of the polynomial:

x^4 + 2x^3 + 2x^2 - 2x -3

According to the Factor Theorem, if a binomial in the form (<em>x</em> - <em>a</em>) is a factor of a polynomial P(x), then P(a) must equal zero.

Our binomial factor is (<em>x</em> + 1) or (<em>x</em> - (-1)). Hence, <em>a</em> = -1.

Let our polynomial be P(x). Find P(-1):

\displaystyle\begin{aligned}  P(-1) &= (-1)^4 + 2(-1)^3 +2(-1)^2 -2(-1) -3 \\&=0\end{aligned}

Therefore, since the resulting value is indeed zero, (<em>x</em> + 1) is indeed a factor of the given polynomial.

In conclusion: yes.

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Answer:

\large \boxed{\frac{1}{15} \text{ lb}}

Step-by-step explanation:

You are starting with ⅖ lb of fudge. Then you cut it into six pieces.

You want to evaluate ⅖ ÷ 6

1. Treat the integer as a fraction

\dfrac{2}{5}\div{\dfrac{6}{1}}

2. Invert the divisor and change divide to multiply

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3. Divide numerator and denominator by 2

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4. Multiply numerators and denominators

\dfrac{1}{5}\times{\dfrac{1}{3}} = \mathbf{\dfrac{1}{15}}\\\\\text{Each piece of fudge weighs $\large \boxed{\mathbf{\frac{1}{15}} \textbf{ lb}}$}

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Answer:

Probability of people choosing chocolate is 27/65

Step-by-step explanation:

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4 0
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Answer:

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Step-by-step explanation:

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Hi there!

Your answer is:

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