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alekssr [168]
3 years ago
8

Differentiate y=2x+200/x with respect to x

Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:

Hello,

\boxed{y'=2-\dfrac{200}{x^2} }\\

Step-by-step explanation:

(f(x)+g(x))'=f'(x)+g'(x)\\\\(2x)'=2*(x)'=2*1=2\\\\(\dfrac{200}{x} )'=200*(x^{-1})'=200*(-1)*x^{-1-1})=-\dfrac{200}{x^2} \\\\\\\boxed{y'=2-\dfrac{200}{x^2} }\\

tia_tia [17]3 years ago
8 0

Answer:

\frac{dy}{dx }  =  2 -   \frac{200}{ {x}^{2} }

Step-by-step explanation:

the \: equation \: can \: be \: rewriten \: as \\ y = 2x +  200 {x}^{ - 1}  \\   \\ now \: differentiate \: the \: equation\ \\   \frac{dy}{dx}   = 2 - 200 {x}^{ - 2}  \\  \frac{dy}{dx}  = 2 - \frac{200}{ {x}^{2} }

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