Question

Differentiate y=2x+200/x with respect to x

Answer 1

Answer:

Hello,

$\boxed{y'=2-\dfrac{200}{x^2} }$

Step-by-step explanation:

$(f(x)+g(x))'=f'(x)+g'(x)\\\\(2x)'=2*(x)'=2*1=2\\\\(\dfrac{200}{x} )'=200*(x^{-1})'=200*(-1)*x^{-1-1})=-\dfrac{200}{x^2} \\\\\\\boxed{y'=2-\dfrac{200}{x^2} }$

Answer 2

Answer:

$\frac{dy}{dx } = 2 - \frac{200}{ {x}^{2} }$

Step-by-step explanation:

$the \: equation \: can \: be \: rewriten \: as \\ y = 2x + 200 {x}^{ - 1} \\ \\ now \: differentiate \: the \: equation\ \\ \frac{dy}{dx} = 2 - 200 {x}^{ - 2} \\ \frac{dy}{dx} = 2 - \frac{200}{ {x}^{2} }$